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Step2247 [10]
3 years ago
8

Find the value of y if VP is an angel bisector, m<2=1+28y and m

Mathematics
1 answer:
galben [10]3 years ago
8 0

Answer:

\boxed{y=1}

Step-by-step explanation:

Since m\angle1=m\angle2 due to \over{VP} is an angle bisector, we have the following:

m\angle1+m\angle2=m\angle XVW\\(1+28y)+(1+28y)=59y-1\\2+56y=59y-1\\2+1=59y-56y\\3=3y\\y=1

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