Question

Find the value of y if VP is an angel bisector, m<2=1+28y and m

Answer 1

Answer:

$\boxed{y=1}$

Step-by-step explanation:

Since $m\angle1=m\angle2$ due to $\over{VP}$ is an angle bisector, we have the following:

$m\angle1+m\angle2=m\angle XVW\\(1+28y)+(1+28y)=59y-1\\2+56y=59y-1\\2+1=59y-56y\\3=3y\\y=1$