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3 years ago

Find the value of y if VP is an angel bisector, m<2=1+28y and m

Mathematics

1 answer:

galben [10]3 years ago

8 0

Answer:

$\boxed{y=1}$

Step-by-step explanation:

Since $m\angle1=m\angle2$ due to $\over{VP}$ is an angle bisector, we have the following:

$m\angle1+m\angle2=m\angle XVW\\(1+28y)+(1+28y)=59y-1\\2+56y=59y-1\\2+1=59y-56y\\3=3y\\y=1$

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The area of a square is found by squaring one of its sides, (A = s2). A certain square has an area of z2 + 18z + 81. Factor the

masya89 [10]

Here is your answer

Given area is

z^2 + 18z + 81

= z^2 + 2× z × 9 + 9^2

[using (a+b)^2= a^2 + 2ab + b^2], we get

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we know that area of a square is represented by side^2.

So, here

Side of square is

$z+9$

HOPE IT IS USEFUL

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2 years ago

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natima [27]

Answer:

Step-by-step explanation:

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3 years ago

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Ierofanga [76]

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3 years ago

For a standard normal distribution,Find P(-1.21 < Z< 2.26)

Mars2501 [29]

Answer:

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11 months ago

Find the product of all positive divisors of 288.

irinina [24]

Answer:

The answer is 1.514571894×10^21.

Step-by-step explanation:

Here, the divisors of 288 are,

1,2,3,4,6,8,9,12,16,18,24,32,36,48,72,96,144,288.

now, their product =1×2×3×4×6×8×9×12×16×18×24×32×36×48×72×96×144×288

=1.514571894×10^21.

is answer. 

Hope it helps...

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2 years ago

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