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azamat
3 years ago
10

Which expression is equivalent to xy^2/9

Mathematics
1 answer:
ddd [48]3 years ago
3 0
X * y^2 
---------  Note that you mut evaluate y^2 before multiplying y^2 by x.
    9
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The product of the ages of a man and his son is 160. In four years time, the man will be four times as old as his son. Find thei
kati45 [8]

Answer:

father = 32    s = 5 y/o

Step-by-step explanation:

f s = 160  ====>   s = 160/f

f+4 = 4 ( s+4)  

f + 4 = 4 (160/f +4)

f + 4 = 640/f + 16

f^2 + 4f = 640 + 16 f

f^2 -12f - 640 = 0      Use Quadratic formula to find  f =  32   then s = 5

3 0
2 years ago
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1 Activity
Alexxx [7]

Answer: See explanation

Step-by-step explanation:

Let the price of apples be represented by a

Let the price of guyabanos be represented by g.

Since Marcel buys 5-star apples for PhP5.00 each and 3 guyabanos for PhP32.50 each. This will be:

C = 5a + 3g

where

a = PhP5.00

g = PhP32.50

c = Total cost

Therefore, an expression for the total cost of the fruits she buys will be:

C = 5a + 3g

C = 5(5.00) + 3(32.50)

The equation for the amount of change the cashier should give her if she gives the cashier PhP200.00 will be:

= 200.00 - 5(5.00) + 3(32.50)

= 200.00 - (25.00 + 97.50)

= 200.00 - 122.50

= Php77.50

7 0
3 years ago
REVIEW EXERCISES Find the deduction per pay period. 27. Annual cost of insurance: $6,800 Employer pays 75% 24 pay periods 28. An
Alexus [3.1K]

Answer:

I hope this is correct

6 0
3 years ago
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(60 POINTS) PLEASE HELP ME!!!
Elan Coil [88]

Answer:

the second option

Step-by-step explanation:

The second option because there is no pattern.

8 0
3 years ago
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A car braked with a constant deceleration of 16ft/s2, producing skid marks measuring 200 feet before coming to a stop. How fast
Llana [10]

Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.

Step-by-step explanation:

The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,

a = - 16ft/s^2

While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.

This means that it travelled a distance,

s = 200 feet

We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.

Since the car came to a stop, its final velocity, v = 0

Applying Newton's equation of motion,

v^2 = u^2 + 2as

0 = u^2 - 2 × 16 × 200

u^2 = 6400

u = √6400

u = 80 ft/s

7 0
3 years ago
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