Hello,
s=48t-16t²
a)
s=0==>16t(3-t)=0==>t=0 or t=3
b)
s>32==>48t-16t²>32===>16(t²-3t+2)<0
Δ=9-8=1
==>16(t-1)(t-2)<0
==>1<t<2 (negative between the roots)
Answer:
both plumbers charge $120 for 3 hours of work
Step-by-step explanation:
1) x=3 and x stands for hours.
2) 120=y and y stands for money charged
so the points (3, 120) show that the plumbers both charge 120 for 3 hrs.