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tia_tia [17]
2 years ago
10

Identify the domain and range of the following relation. {(7,-2), (7,4), (7,6), (7,-4), (7,1)}

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
6 0

Answer:

B.

Step-by-step explanation:

Domain is the x-coordinate and the range is the y-coordinate.

B. Domain: {7}

Range: {-4, -2, 1, 4, 6}

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What is the mistake?<br><br> 3a+4b=7ab
MrRa [10]

Answer:

You cannot add like terms like that.

Step-by-step explanation:

The terms are supposed to be added together, by combining them like that you are multiplying them together.

6 0
3 years ago
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Match them together to correct answer
Verizon [17]

ANSWER

Frequency=2

Midline =3

Amplitude =5

Period =π

EXPLANATION

We have:

f(x) = 5 \cos(x)  + 3

The given function is of the form;

f(x) = a\cos(bx)  + c

where

a=|5| =5 is the amplitude

and b=2 is the frequency.

and 2π/b=2π/2=π

The range of the given function is

8≤y≤-2

The midline is

\frac{8  + - 2}{2}  =  \frac{6}{2}  = 3

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3 years ago
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The first term in the sequence is 1, and each other term is 5 more than three times the previous term.
marin [14]

a_1=1, a_n=a_{n-1}+5 (n>1).

Hope this helps.

6 0
3 years ago
NEED HELP RN!!! PLS ☹️
Korolek [52]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Look at the figure shown below:
boyakko [2]

These are the steps, with their explanations and conclusions:


1) Draw two triangles: ΔRSP and ΔQSP.


2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).


3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.


4) The segment SP is common to both ΔRSP and Δ QSP.


5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.


Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q


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3 years ago
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