Answer:
22.5
Step-by-step explanation: you just divide the two numbers :)
Answer:
Its B
Step-by-step explanation:
This question is incomplete.
The complete question says;
The two-way table shows the number of hours students studied and whether they studied independently or with a study group.
What is the relative frequency of students that studied independently for more than 2 hours to the total number of students that studied independently?
a) 0.4 c) 0.25
b) 0.33 d) 0.11
Table is attached as image
Answer: C (0.25)
The number of students that studied for more than 2 hours as given in the table are 4.
The total number of people that studied independently include those that studied less than 2 hours and those that studied for more than 2 hours.
Those that studied less than 2 hours independently are 12.
Those that studied more than 2 hours independently are 4.
Hence the total number of people that studied independently is 16.
Therefore the relative frequency of students that studied independently for more than 2 hours to the total number of students that studied independently would be = 4/16 = 1/4 = 0.25.
Answer:
correct option is C) 2.8
Step-by-step explanation:
given data
string vibrates form = 8 loops
in water loop formed = 10 loops
solution
we consider mass of stone = m
string length = l
frequency of tuning = f
volume = v
density of stone =
case (1)
when 8 loop form with 2 adjacent node is
so here
..............1

and we know velocity is express as
velocity = frequency × wavelength .....................2
= f ×
here tension = mg
so
= f ×
..........................3
and
case (2)
when 8 loop form with 2 adjacent node is
..............4

when block is immersed
equilibrium eq will be
Tenion + force of buoyancy = mg
T + v ×
× g = mg
and
T = v ×
- v ×
× g
from equation 2
f ×
= f ×
.......................5
now we divide eq 5 by the eq 3

solve irt we get

so
relative density 
relative density = 2.78 ≈ 2.8
so correct option is C) 2.8
y=4x-11 is the correct equation