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leonid [27]
3 years ago
13

Is it possible to replace discrimination with respect how brainly

SAT
1 answer:
IRISSAK [1]3 years ago
5 0

Answer:

yus its posable

Explanation:

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 <span>Propaganda is used by certain groups to persuade or scare others into adopting their beliefs, whether it's political, religious or philosophical. 

In the context of history, this is often done either by a government to keep people on their side, or by other groups to cause a revolution.

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Infectious diseases can be classified on the basis of:
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The agents of infection can be divided into different groups on the basis of their size, biochemical characteristics, or manner in which they interact with the human host. The groups of organisms that cause infectious diseases are categorized as bacteria, viruses, fungi, and parasites.
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If joe to go decides that a joint venture has too much risk.
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3 years ago
Assuming ideal solution behavior, how many liters of hcl gas, measured at 30. 0 °c and 745 torr, are required to prepare 1. 25 l
Nostrana [21]

The volume of HCl gas required to prepare the solution is 101.54 L

<h3>How to determine the mole of HCl </h3>
  • Volume of solution = 1.25 L
  • Molarity = 3.20 M
  • Mole of HCl =?

Mole = Molarity x Volume

Mole of HCl = 3.2 × 1.25

Mole of HCl = 4 moles

<h3>How to determine the volume of HCl </h3>
  • Number of mole (n) = 4 moles
  • Temperature (T) = 30 °C = 30 + 273 = 303 K
  • Pressure (P) = 745 torr = 745 / 760 = 0.98 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Volume =?

Using the ideal gas equation, the volume of the HCl gas can be obtained as follow:

PV = nRT

Divide both side by P

V = nRT / P

V = (4 × 0.0821 × 303) / 0.98

V = 101.54 L

Learn more about ideal gas equation:

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3 0
2 years ago
A typical neutron star has a mass of about 1. 5msun and a radius of 10 kilometers
Triss [41]

How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.

<h3>Density of the Neutron star</h3>

Density

ρ = m / V

Where:

ρ= density

m = mass of the planet 5.98 10²⁴ km

V =volume of the spherical layer

Volume of a sphere

Volume = 4/3 π r³

Mass = 1.5 = 1.5 1,991 10³⁰

Mass= 2.99 10³⁰ kg

Density:

ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]

ρ is = 7.13 10 17 kg / m³

V = 5.98 10²⁴ / 7.13 10¹⁷

V = 8,387 10⁶ m³

Thickness of the layer

V = 4π r² e

e = V / 4π r

e = 8,387 10⁶ / [4π (10 10³)²]

e = 6.67 10⁻³ m

Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.

Learn more about Density of the Neutron star here:brainly.com/question/15700804

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