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aalyn [17]
3 years ago
12

What is 5 1/4 x 4 1/5

Mathematics
2 answers:
DIA [1.3K]3 years ago
8 0

Answer: 22\frac{1}{20} or 22.05

Step-by-step explanation:

\frac{21}{4} × \frac{21}{5}

=\frac{441}{20}

22\frac{1}{20} or 22.05

please give me a brainliest answer

dalvyx [7]3 years ago
5 0

Answer:

The answer to your question is 22 1/20

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In a bag, there are 25 marbles. 8 are red and the rest are green. If there are 100 marbles in. a bag, how many are red? *
Sophie [7]

Answer:

32 marbles are red.

Step-by-step explanation:

Think of a quarter, 4 of them equal a dollar.

25 x 4 = 100

So, you will multiply 8 by 4.

8 x 4 = 32

4 0
3 years ago
Rooter Plus charges a $25 service fee plus $40 per hour of work done. Is this a proportional or non-proportional relationship?
Dominik [7]

Answer:

Non-proportional; the rate of change is $40/hour

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line <u>and the line passes through the origin</u>

Let

x -----> the number of hours

y ----> The total charge in dollars

The equation of the line in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-intercept

we have

m=40\ \$/h\\b=\$25

substitute

y=40x+25

This relationship is not proportional, because the line not passes through the origin

therefore

Non-proportional; the rate of change is $40/hour

5 0
3 years ago
Let sin(47o)=0.7314 . Enter an angle measure (β ), in degrees, for cos(β)=0.7314
amid [387]
Sinx = cosb => x + b = 90 <=> b = 90 - 47 = 43o
8 0
3 years ago
Plz Help! I need this ASAP! I will give brainlest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
viktelen [127]

7)  164.26

8)77.08

9)2405.364

steps for 7) attached

steps for 8)

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csf%5Clim_%7Bx%20%5Cto%200%20%7D%20%5Cfrac%7B1%20-%20%5Cprod%20%5Climits_%
xxTIMURxx [149]

To demonstrate a method for computing the limit itself, let's pick a small value of n. If n = 3, then our limit is

\displaystyle \lim_{x \to 0 } \frac{1 - \prod \limits_{k = 2}^{3} \sqrt[k]{\cos(kx)} }{ {x}^{2} }

Let a = 1 and b the cosine product, and write them as

\dfrac{a - b}{x^2}

with

b = \sqrt{\cos(2x)} \sqrt[3]{\cos(3x)} = \sqrt[6]{\cos^3(2x)} \sqrt[6]{\cos^2(3x)} = \left(\cos^3(2x) \cos^2(3x)\right)^{\frac16}

Now we use the identity

a^n-b^n = (a-b)\left(a^{n-1}+a^{n-2}b+a^{n-3}b^2+\cdots a^2b^{n-3}+ab^{n-2}+b^{n-1}\right)

to rationalize the numerator. This gives

\displaystyle \frac{a^6-b^6}{x^2 \left(a^5+a^4b+a^3b^2+a^2b^3+ab^4+b^5\right)}

As x approaches 0, both a and b approach 1, so the polynomial in a and b in the denominator approaches 6, and our original limit reduces to

\displaystyle \frac16 \lim_{x\to0} \frac{1-\cos^3(2x)\cos^2(3x)}{x^2}

For the remaining limit, use the Taylor expansion for cos(x) :

\cos(x) = 1 - \dfrac{x^2}2 + \mathcal{O}(x^4)

where \mathcal{O}(x^4) essentially means that all the other terms in the expansion grow as quickly as or faster than x⁴; in other words, the expansion behaves asymptotically like x⁴. As x approaches 0, all these terms go to 0 as well.

Then

\displaystyle \cos^3(2x) \cos^2(3x) = \left(1 - 2x^2\right)^3 \left(1 - \frac{9x^2}2\right)^2

\displaystyle \cos^3(2x) \cos^2(3x) = \left(1 - 6x^2 + 12x^4 - 8x^6\right) \left(1 - 9x^2 + \frac{81x^4}4\right)

\displaystyle \cos^3(2x) \cos^2(3x) = 1 - 15x^2 + \mathcal{O}(x^4)

so in our limit, the constant terms cancel, and the asymptotic terms go to 0, and we end up with

\displaystyle \frac16 \lim_{x\to0} \frac{15x^2}{x^2} = \frac{15}6 = \frac52

Unfortunately, this doesn't agree with the limit we want, so n ≠ 3. But you can try applying this method for larger n, or computing a more general result.

Edit: some scratch work suggests the limit is 10 for n = 6.

6 0
2 years ago
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