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3 years ago

7

Does anyone know the answer for the question below.

2 answers:

Korolek [52]3 years ago

8 0

x³ + x² - x - 10 =

= x³ - 2x² + 3x² - 6x + 5x - 10

= x²(x - 2) + 3x(x - 2) + 5(x - 2)

= (x - 2)(x² + 3x + 5)

(x - 2)(x² + 3x + 5)/(x - 2)

= x² + 3x + 5

taurus [48]3 years ago

5 0

Answer: option D is the answer

Step-by-step explanation:

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kodGreya [7K]

Answer:

(1) $g[f(x)]=\frac{8x-1}{12x-4}$

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Given functions f(x) = (4x-1)

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(2) for $g^{-1}(x)$ , rewrite the function g(x) in terms of an equation

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⇒ $\frac{8x-3x+4+1}{3x-1}=(x-1)$

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⇒ $5x+5=(3x-1)(x-1)$

⇒ $5x+5=3x^2-3x-x+1$

⇒ $5x+5=3x^2-4x+1$

⇒ $3x^2-9x-4=0$

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$x=\frac{9\pm\sqrt{81+48} }{6}$

$x=\frac{9\pm\sqrt{129} }{6}$

$x=\frac{9+\sqrt{129} }{6}, \frac{9-\sqrt{129} }{6}$

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