Answer:
Step-by-step explanation:
3. slope of CB = rise/run = 5/12 BF = 5 CF = 12
BF ⊥ DF
DB (seg of two farthest points) = √BF²+DF² = √5²+32² = √1049 = 32.4
4. f(x) = 2x² - 5x -3 vertex : A (h,k) for f(x) = ax² + bx +c
h = - b/2a = - (-5 / 4) = 5/4
f = f(h) = 2*(5/4)² - 5*(5/4) - 3 =25/8 - 25/4 -3 = -49/8
A (5/4 , - 49/8) i.e. (1.25 , - 6.13)
negative root: 2x² - 5x -3 = (2x+1) (x- 3) x = - 1/2 y = 0
B (- 1/2 , 0)
x coordinate of AB: 1/2 (1.25 + -0.5) = 0.375
Answer:
14
Step-by-step explanation:
14
So first you distribute the 5 to the x and the +2 and get
5x+10=3(x+8)
then you distribute the 3 to the other x and the +8 and get
5x+10=3x+24
subtract 3x from both sides
2x+10=24
subtract 10 from both sides and get
2x=14
divide both sides by 2 and get
x=7
Answer:
3
Step-by-step explanation:
mhm for your brother
anyways...
2x-3+6x = 21
Adding like terms
8x -3 = 21
Adding 3 on both sides
8x = 24
Dividing both sides by 8
x = 3
Answer:
Step-by-step explanation:
The trigonometric identity is :
We need to express secθ in terms of tanθ.
The above equation becomes,
Hence, this is the required solution.
