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Lena [83]
3 years ago
6

The value of a + b + c for equation 2 Y - x = 7 is ​

Mathematics
1 answer:
morpeh [17]3 years ago
6 0

Answer:

Correct option is

B

1.x+0.y=7

x=7 can be written as, 1.x+0.y=7 as the coefficient of x is 1 and that of y is 0. Step-by-step explanation:

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If b is the midpoint of AC, which of the following choices is the value of x?
katrin [286]
If B is the midpoint of AC, that means that the distances from A to B and B to C are the same. The distance from A to B is 8x + 4, and the distance from B to C is 10x - 6, so we can set these two equivalent:

8x + 4 = 10x - 6

Solving for x:

4 = 2x - 6 (subtract 8x from both sides)
10 = 2x (add 6 to both sides)
5 = x (divide both sides by 2)

So, x = 5, which is the second option given.
8 0
4 years ago
Two problems I can’t get is; 94-4.8 I know the answer is 89.2 but how?
vekshin1

Answer:

have the correct answer

Step-by-step explanation:

a-line the decimals nd subtract

6 0
3 years ago
When does expanding and simplifying a(b+c) result in a positive value for ac
TiliK225 [7]

Answer:


Step-by-step explanation:

(ab + bc)(ab + bc)

Simplifying

(ab + bc)(ab + bc)

Multiply (ab + bc) * (ab + bc)

(ab(ab + bc) + bc(ab + bc))

((ab * ab + bc * ab) + bc(ab + bc))

Reorder the terms:

((ab2c + a2b2) + bc(ab + bc))

((ab2c + a2b2) + bc(ab + bc))

(ab2c + a2b2 + (ab * bc + bc * bc))

(ab2c + a2b2 + (ab2c + b2c2))

Reorder the terms:

(ab2c + ab2c + a2b2 + b2c2)

Combine like terms: ab2c + ab2c = 2ab2c

(2ab2c + a2b2 + b2c2)

7 0
4 years ago
What is the width of the rectangle shown?
nika2105 [10]
I think the answer is 2( 4x+3)(x-2)
7 0
3 years ago
It’s not 0.615 , or 0.75 or the one shown in the picture
Dafna1 [17]
2.40714

1) Let's evaluate that expression, given that a=4.9, b=-7, and c=-0.5

\begin{gathered} a^3\div b^2+c^3 \\ (4.9)^3\div(-7)^2+(-0.5)^3= \\ \frac{4.9^3}{\left(-7\right)^2+\left(-0.5\right)^3} \\  \\ \frac{4.9^3}{48.875} \\  \\ \frac{117.649}{48.875} \\  \\ 2.40714 \end{gathered}

Note that we have rewritten it as a fraction so that we can easily operate. Also, we have applied here the PEMDAS order of operations, prioritizing the exponents.

6 0
1 year ago
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