First you put (x+5) into the initial function wherever you see x so it becomes
(x+5)^2+3(x+5)-10=x^2+kx+30
(x^2+5x+25)+(3x+15)-10 simplified left side
x^2+8x+30 fully simplified left side
thus k=8
x^2+8x+30=0 to find 0s
-4 + 3.7416573867739i
<span>-4 - 3.7416573867739i
</span>these are the roots you find after using the quadratic formula
the second one is the smallest
2((x+2)(x+2)}-4=28
2{x^2 + 4x + 4}-4=28
2x^2 +4x=28
2(x^2+2x)=28
x^2+2x=28/2
x^2+2x=14
The answer is 2m because it is like if you had 3 mangoes and you eat one you would have 2 mangoes.<span />
Answer:
Inflection points. It's where the second derivative of the function is equal to zero
Step-by-step explanation:
