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san4es73 [151]
3 years ago
14

(2x4 + 3x – 5) + (6x4 + 2x2 + 2) +

Mathematics
1 answer:
ElenaW [278]3 years ago
7 0

Answer:

Simplify the expression.

8x4+3x+2x2−3

Write in standard form.

8x4+2x2+3x−3

Step-by-step explanation:

i think this is the answer?

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The stem-and-leaf plot shows the ages of customers who were interviewed in a survey by a store.
Solnce55 [7]

Answer:

Step-by-step explanation:

Given is a steam and leaf plot.

This shows the age of customers who were interviewed in a survey by a store.

From the plot we can say that 10th digit is represented by the stem

For greater than 32, obviously 1,2 stem valus will not work.

For stem 3, we can leave 30 and 31 start with 2 in leaf and 3 n stem

We have 32, onwards 7 persons

Similarly for 4, we have 6, for 5 we have 5, for 6 we have 4 and for 7 we have 1

Total number of customers who have ages more than 32 years = 21

8 0
3 years ago
Help me pls I need it fast
LuckyWell [14K]

Answer:

I don't know does it fold up or anything?

Step-by-step explanation:

3 0
3 years ago
Which are right triangles that can be formed using a diagonal through the interior of the cube? Select all that apply.
photoshop1234 [79]

Answer:

triangle AEH, triangle CFG, triangle BFG, and triangle DEG.

so b,c,e,f

this is right for e2020.

8 0
3 years ago
Read 2 more answers
Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.
finlep [7]

Answer:

a) v = \frac{[L]}{[T]} = LT^{-1}

b) a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}

c) \int v dt = s(t) = [L]=L

d) \int a dt = v(t) = [L][T]^{-1}=LT^{-1}

e) \frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

v = \frac{ds}{dt}

a= \frac{dv}{dt}

Part a

If we do the dimensional analysis for v we got:

v = \frac{[L]}{[T]} = LT^{-1}

Part b

For the acceleration we can use the result obtained from part a and we got:

a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}

Part c

From definition if we do the integral of the velocity respect to t we got the position:

\int v dt = s(t)

And the dimensional analysis for the position is:

\int v dt = s(t) = [L]=L

Part d

The integral for the acceleration respect to the time is the velocity:

\int a dt = v(t)

And the dimensional analysis for the position is:

\int a dt = v(t) = [L][T]^{-1}=LT^{-1}

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}

7 0
3 years ago
If f(x) varies directly with x and f(x) = 72 when x = 6, find the value of f(x) when x = 3.
Levart [38]

Answer:

36

Step-by-step explanation:

Since f(x) varies directly with x, f(x) can be expressed alternatively as \[f(x) = k * x\] where k is a constant value.

Given that f(x) is 72 when the value of x is 6.

This implies, \[72 = k * 6\]

Simplifying and rearranging the equation to find the value of k:

k = \frac{72}{6}

Hence k = 12

Or, \[f(x) = 12 * x\]

When x = 3, \[f(x) = 12 *3 \]

Or in other words, the value of f(x) when x=3 is 36

4 0
3 years ago
Read 2 more answers
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