The actual skate park's perimeter is 130 inches.
Explanation:
Step 1; Assume the initial garden has a width of y inches. It is given that the length is 25 inches. The perimeter of any given rectangle is twice the sum of the length and the width of the same rectangle. The initial perimeter is given as 80 inches.
Perimeter = 2 × (length of the rectange + width of the rectangle).
80 = 2 × (25 + y), 40 = 25 + y, y = 40 - 25 = 15
So the initial park has a width of 15 inches.
Step 2; Now we calculate the actual skate park's perimeter. The length is given as 50 inches and the width was found to be 15 inches.
Perimeter = 2 × (length of the rectange + width of the rectangle).
Perimeter = 2 × (50 + 15) = 2 × 65 = 130 inches.
The answer is the second one
Answer:
a21 = -61
Step-by-step explanation:
(subtract to eliminate a₁)
9 = -3d
d = -3
-19 = a₁ + (6)(-3)
-1 = a
a21 = -1 + (21 - 1)(-3)
= -61
I'm assuming it is -m, +m, -m, +m etc..
