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3 years ago

What equation is being graphed?

Mathematics

1 answer:

Alex3 years ago

7 0

Answer:

D. y-4= -3/2(x+5)

Step-by-step explanation:

Firstly, taking two valid ordered pairs from the graph:

(-2,4) and (2,-2)

Using Delta y over Delta x, we are able to obtain m as -3/2

Next,

The following is the point-slope formula:

y-y₁=m(x-x₁)

Based on the graph, (4,-5) can be spotted as a definite ordered pair

Therefore, y-4= -3/2(x+5) fits the graph best and has the appropriate m value.

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If x = 5, find the value of a) x2 b) (x + 3)2

PtichkaEL [24]

Answer: a) = 10

b) = 16

Step-by-step explanation:

a) as x = 5 so putting the value of x in given equation

5 multiplied by 2 is equal to 10

b) Putting value of x in given equation

= (5 + 3) 2

According to BODMAS solve the brackets first

= 8 x 2

= 16

3 0

3 years ago

Find the inverse of each function.

weeeeeb [17]

The inverse of a function is the opposite of the function

<h3>How to determine the inverse functions</h3>

1) y = log2 (3x)

Swap the positions of x and y

$x = \log_2(3y)$

Apply the exponential rule

$2^x = 3y$

Make y the subject

$y = \frac{2^x}3$

Hence, the inverse function is: $y = \frac{2^x}3$

2) y=log3(x-1)

Swap x and y

$x = \log_3(y - 1)$

Apply exponent rule

$3^x = y - 1$

Make y the subject

$y = 3^x + 1$

Hence, the inverse function is: $y = 3^x + 1$

3) y=-2log x

Swap x and y

$x=-2\log y$

Divide both sides by -2

$-0.5x=\log y$

Apply exponent rule

$y = 10^{-0.5x}$

Hence, the inverse function is: $y = 10^{-0.5x}$

4) y=log6(3x)

Swap x and y

$x = \log_6(3y)$

Apply exponent rule

$3y = 6^x$

Make y the subject

$y = \frac{6^x}{3}$

Hence, the inverse function is: $y = \frac{6^x}{3}$

5)y=log3(x+2)

Swap x and y

$x = \log_3(y + 2)$

Apply exponent rule

$y + 2 = 3^x$

Make y the subject

$y = 3^x - 2$

Hence, the inverse function is: $y = 3^x - 2$

6) y=log3(5^3)

Swap x and y

$x = \log_3(5^3)$

Hence, the inverse function is: $x = \log_3(5^3)$

7) y=6^x+5

Swap x and y

$x = 6^y + 5$

Subtract 5 from both sides

$6^y = x - 5$

Apply logarithm

$y = \log_6(x - 5)$

Hence, the inverse function is: $y = \log_6(x - 5)$

9) y=log3 2^x

Swap x and y

$x = \log_3(2^y)$

Apply exponent rule

$2^y = 3^x$

Apply logarithm

$y = \log_2(3^x)$

Hence, the inverse function is: $y = \log_2(3^x)$

10) y=3^x -7

Swap x and y

$x = 3^y - 7$

Add 7 to both sides

$3^y = x + 7$

Apply logarithm

$y = \log_3(x + 7)$

Hence, the inverse function is: $y = \log_3(x + 7)$

Read more about inverse functions at:

brainly.com/question/14391067

4 0

2 years ago

Plz plz plz help I don’t get this

Bumek [7]

It looks like it counts up by 2 when adding. so add 4, then add 6, then add 8, then add 10, etc. to find the output you simply add 2 more than the last time you added, to find the input, you subtract 2 more than last time. hope this makes sense haha.

6 0

4 years ago

Read 2 more answers

How would I solve this problem?

Nataliya [291]

The area of the garden enclosed by the fencing is

A(x, y) = xy

and is constrained by its perimeter,

P = x + 2y = 200

Solve for x in the constraint equation:

x = 200 - 2y

Substitute this into the area function to get a function of one variable:

A(200 - 2y, y) = A(y) = 200y - 2y²

Differentiate A with respect to y :

dA/dy = 200 - 4y

Find the critical points of A :

200 - 4y = 0 ⇒ 4y = 200 ⇒ y = 50

Compute the second derivative of A:

d²A/dy² = -4 < 0

Since the second derivative is always negative, the critical point is a local maximum.

If y = 50, then x = 200 - 2•50 = 100. So the farmer can maximize the garden area by building a (100 ft) × (50 ft) fence.

3 0

2 years ago

What is the length of the hypotenuse of the triangle ?

Shkiper50 [21]

Answer:

The length of the hypotenuse of the triangle is about 14.14 units.

Step-by-step explanation:

You can determine this by using the Pythagorean Theorem.

a^2 + b^2 = c^2

To find the hypotenuse, take sides a and b (10 and 10) and square them. You get 100. When you add 100 and 100 together, you get 200, which equals c^2. Find the square root of 200 to find the hypotenuse.

8 0

4 years ago

Read 2 more answers