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Semmy [17]
3 years ago
10

What is 4.23x10-7 in standard form

Mathematics
1 answer:
alisha [4.7K]3 years ago
4 0

Answer:

i think it is all ready in standard form

is the original number 0.000000423 if yes then it is in standard form

You might be interested in
a) What is an alternating series? An alternating series is a whose terms are__________ . (b) Under what conditions does an alter
andriy [413]

Answer:

a) An alternating series is a whose terms are alternately positive and negative

b) An alternating series \sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n where bn = |an|, converges if 0< b_{n+1} \leq b_n for all n, and \lim_{n \to \infty} b_n = 0

c) The error involved in using the partial sum sn as an approximation to the total sum s is the remainder Rn = s − sn and the size of the error is bn + 1

Step-by-step explanation:

<em>Part a</em>

An Alternating series is an infinite series given on these three possible general forms given by:

\sum_{n=0}^{\infty} (-1)^{n} b_n

\sum_{n=0}^{\infty} (-1)^{n+1} b_n

\sum_{n=0}^{\infty} (-1)^{n-1} b_n

For all a_n >0, \forall n

The initial counter can be n=0 or n =1. Based on the pattern of the series the signs of the general terms alternately positive and negative.

<em>Part b</em>

An alternating series \sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n where bn = |an|  converges if 0< b_{n+1} \leq b_n for all n and \lim_{n \to \infty} b_n =0

Is necessary that limit when n tends to infinity for the nth term of bn converges to 0, because this is one of two conditions in order to an alternate series converges, the two conditions are given by the following theorem:

<em>Theorem (Alternating series test)</em>

If a sequence of positive terms {bn} is monotonically decreasing and

<em>\lim_{n \to \infty} b_n = 0<em>, then the alternating series \sum (-1)^{n-1} b_n converges if:</em></em>

<em>i) 0 \leq b_{n+1} \leq b_n \forall n</em>

<em>ii) \lim_{n \to \infty} b_n = 0</em>

then <em>\sum_{n=1}^{\infty}(-1)^{n-1} b_n  converges</em>

<em>Proof</em>

For this proof we just need to consider the sum for a subsequence of even partial sums. We will see that the subsequence is monotonically increasing. And by the monotonic sequence theorem the limit for this subsquence when we approach to infinity is a defined term, let's say, s. So then the we have a bound and then

|s_n -s| < \epsilon for all n, and that implies that the series converges to a value, s.

And this complete the proof.

<em>Part c</em>

An important term is the partial sum of a series and that is defined as the sum of the first n terms in the series

By definition the Remainder of a Series is The difference between the nth partial sum and the sum of a series, on this form:

Rn = s - sn

Where s_n represent the partial sum for the series and s the total for the sum.

Is important to notice that the size of the error is at most b_{n+1} by the following theorem:

<em>Theorem (Alternating series sum estimation)</em>

<em>If  \sum (-1)^{n-1} b_n  is the sum of an alternating series that satisfies</em>

<em>i) 0 \leq b_{n+1} \leq b_n \forall n</em>

<em>ii) \lim_{n \to \infty} b_n = 0</em>

Then then \mid s - s_n \mid \leq b_{n+1}

<em>Proof</em>

In the proof of the alternating series test, and we analyze the subsequence, s we will notice that are monotonically decreasing. So then based on this the sequence of partial sums sn oscillates around s so that the sum s always lies between any  two consecutive partial sums sn and sn+1.

\mid{s -s_n} \mid \leq \mid{s_{n+1} -s_n}\mid = b_{n+1}

And this complete the proof.

5 0
4 years ago
A thermometer is taken from an inside room to the outside, where the air temperature is 20° f. after 1 minute the thermometer re
fomenos

The change in the temperature is proportional to the difference in temperatures. Let's call the initial temperature of the room and the thermometer E_0 and the current temperature E(t) where t is the elapsed time in minutes.  The outside temperature is 20 F.

Newton's Law of Cooling:

E(t) - 20 = (E_0 - 20) e^{- k t}

We're given E(1)=70 \textrm{ and } E(5)=45

70-20 = (E_0 - 20) e^{-k}

45-20 =(E_0 - 20) e^{-5k}

Dividing,

\dfrac{50}{25}=e^{4k}

k = \dfrac 1 4 \ln 2

Now,

E(t) - 20 = (E_0 - 20) e^{- k t}

E_0 = 20 + (E(t) - 20)e^{k t}

E_0 = 20 + (E(1) - 20)e^{k}

E_0 = 20 + (70 - 20)e^{\ln 2/4}

E_0 = 20 + 50 \cdot 2^{1/4} \approx 79.46 \textrm{ degrees F}


3 0
4 years ago
Solve the right triangle ABC, with C = 90°.
Yanka [14]
Answers are as follows
B = 51.5
a = 34.6
c = 55.6
6 0
2 years ago
Can someone help me understand what they mean by “interpretation”
zhuklara [117]

Answer:

is the act of explaining, reframing, or otherwise showing your own understanding of something.

Step-by-step explanation:

4 0
3 years ago
Find the TWO integers whos product is -12 and whose sum is 1<br>​
irina [24]

Answer:

The two INTEGERS are :-

-3 and +4

-3 × (+4) gives us -12

-3 + (+4) gives us 1

hope it helps

have a nice day

5 0
3 years ago
Read 2 more answers
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