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3 years ago

How do i do 5(x-3)=45

Mathematics

1 answer:

Nady [450]3 years ago

7 0

Answer:

Step-by-step explanation:

Simplifying

5(x + 3) = 45

Reorder the terms:

5(3 + x) = 45

(3 * 5 + x * 5) = 45

(15 + 5x) = 45

Solving

15 + 5x = 45

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-15' to each side of the equation.

15 + -15 + 5x = 45 + -15

Combine like terms: 15 + -15 = 0

0 + 5x = 45 + -15

5x = 45 + -15

Combine like terms: 45 + -15 = 30

5x = 30

Divide each side by '5'.

x = 6

Simplifying

x = 6

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Compute (3/4)*(8/9)*(15/16)*(24/25)*(35/36)*(48/49)*(63/64)*(80/81)*(99/100) Express your answer in the simplest way possible. (

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Answer:

$(\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}) = \frac{11}{20}$

Step-by-step explanation:

Given

$(\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100})$

Required

Simplify

For clarity, group the expression in threes

$((\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

Evaluate the first group [Divide 8 by 4]

$((\frac{3}{1})*(\frac{2}{9})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

[Divide 9 by 3]

$((\frac{1}{1})*(\frac{2}{3})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

$((\frac{2}{3})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

[Divide 15 by 3]

$((\frac{2}{1})*(\frac{5}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

[Divide 16 by 2]

$((\frac{1}{1})*(\frac{5}{8}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

$(\frac{5}{8})*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

Evaluate the second group [Divide 35 and 25 by 5]

$(\frac{5}{8})*((\frac{24}{5})*(\frac{7}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

[Divide 49 by 7]

$(\frac{5}{8})*((\frac{24}{5})*(\frac{1}{3})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

[Divide 24 by 3]

$(\frac{5}{8})*((\frac{8}{5})*(\frac{1}{1})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

$(\frac{5}{8})*((\frac{8}{5})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

Merge the first and second group

$((\frac{5}{8})*(\frac{8}{5})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

$(1*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

$(\frac{4}{7})*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

Evaluate the last group [Divide 99 by 9]

$(\frac{4}{7})*((\frac{63}{64})*(\frac{80}{9})*(\frac{11}{100}))$

[Divide 63 by 9]

$(\frac{4}{7})*((\frac{7}{64})*(\frac{80}{1})*(\frac{11}{100}))$

[Divide 64 and 80 by 8]

$(\frac{4}{7})*((\frac{7}{8})*(\frac{10}{1})*(\frac{11}{100}))$

[Divide 10 and 4 by 2]

$(\frac{4}{7})*((\frac{7}{4})*(\frac{5}{1})*(\frac{11}{100}))$

[Divide 100 by 5]

$(\frac{4}{7})*((\frac{7}{4})*(\frac{1}{1})*(\frac{11}{20}))$

$(\frac{4}{7})*((\frac{7}{4})*(\frac{11}{20}))$

$(\frac{4}{7})*(\frac{7}{4})*(\frac{11}{20})$

$1*(\frac{11}{20})$

$\frac{11}{20}$

Hence;

$(\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}) = \frac{11}{20}$

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3 years ago

What is the value of x?

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The sum of a polygon's angles are 540.

When you add all the angles together here, you get 456.

Now subtract 456 from 540.

540 - 456 = 84

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3 years ago