Answer:
centre = (1, - 3 )
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
(x - 1)² + (y + 3)² = 73 ← is in standard form
with (h, k ) = (1, - 3 ) ← centre
1. x=6
2. y=6
3. x=10
4. y=10
1.c+9= 19
2. 9-y=7
3. 5y=30
4. u-u=0
1. 2(3x2 - 5x3)
2(6-15)
2x(-9)=18
9514 1404 393
Answer:
√629 ≈ 25.08
Step-by-step explanation:
The distance formula is useful for this.
d = √((x2 -x1)² +(y2 -y1)²)
d = √((-12 -13)² +(6 -8)²) = √(625 +4) = √629 ≈ 25.08
The distance between the points is about 25.08 units.
Answer:
is this required answer
Step-by-step explanation:
AB=3x-2
=3*8-2
=22
3x - 2y = 13
-2y = -3x + 13
y = 3/2x - 13/2...slope is 3/2, y int is -13/2
2x + 3y = -16
3y = -2x - 16
y = -2/3x - 16/3...slope = -2/3, y int is -16/3
perpendicular lines will have negative reciprocal slopes. To find the negative reciprocal of a number, flip the number and change the sign.
On the 1st equation, the slope was 3/2....find its negative reciprocal.....flip it, making it 2/3....change the sign...making it -2/3. So the negative reciprocal of 3/2 is -2/3.
So if one equation has a slope of 3/2 and another equation has a slope of -2/3, then these lines are perpendicular <==