Yes , it’s true. In a known-plaintext attack (kpa), the cryptanalyst can only view a small portion of encrypted data, and he or she has no control over what that data might be.
The attacker also has access to one or more pairs of plaintext/ciphertext in a Known Plaintext Attack (KPA). Specifically, consider the scenario where key and plaintext were used to derive the ciphertext (either of which the attacker is trying to find). The attacker is also aware of what are the locations of the output from key encrypting. That is, the assailant is aware of a pair. They might be familiar with further pairings (obtained with the same key).
A straightforward illustration would be if the unencrypted messages had a set expiration date after which they would become publicly available. such as the location of a planned public event. The coordinates are encrypted and kept secret prior to the event. But when the incident occurs, the attacker has discovered the value of the coordinates /plaintext while the coordinates were decrypted (without knowing the key).
In general, a cipher is easier to break the more plaintext/ciphertext pairs that are known.
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Answer:
Logical Expressions
Explanation:
The expressions that have logical statements which could be "true or false" are known as logical expressions. These types of expressions are also known as Boolean Expressions.
These expression are used in computer programming. The purpose of these expressions in programming is to make a decision that could be based on different conditions. These conditions could be true or false. This is the main reason that. logical expression makes best sense for values received in true or false.
Answer:
64 K bytes = 65536 bytes
32 M bytes = 33554432 bytes
Explanation:
The question expect the number of bytes in binary instead of decimal. So this is important to understand that:
- 1K bytes = 1024 bytes (in binary)
Therefore,
- 64 Kb = 64 x 1024 = 65536 bytes
Using the similar calculation logic, we know
- 1M bytes = 1024 x 1024 = 1048576 bytes (in binary)
Therefore,
- 32 M bytes = 32 x 1048576 = 33554432 bytes
All of the answers above are correct
So, you can be able to make a prediction and understand the cycle.
