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2 years ago

Just help me out yall see what to do.the first one

Mathematics

2 answers:

Oksanka [162]2 years ago

6 0

Skating party & male=4
Total & male=19
Bowling party & female=3
Pool party & total=12
Skating party & total=14
Bowling party & total=11

marshall27 [118]2 years ago

5 0

Answer:

sorry way to confuseing

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It took Freddy 1/2 hr to paint 1/5 of a fence. How long in minutes will it take him to paint the whole fence? I NEED THIS ASAP

kvasek [131]

150 minutes, multiply the 30 minutes (1/2hr) by the 1/5 of fence (x5)

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2 years ago

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Find the distance between 2-4i and d 6+i

liq [111]

Answer:

7.211

Step-by-step explanation:

-For two points in the complex plane, the distance between the points is the modulus of the of the difference of the two complex numbers.

-Point 2-4i has the coordinates (2,-4)

-Point 6+i has the coordinates (6,1)

#We must find the distance between the two coordinates (2,-4) and (6,1):

$=\sqrt{(6-2)^2+(1--4)^2}\\\\=\sqrt{4^2+6^2}\\\\=\sqrt{52}\\\\=7.211$

Hence, the distance between the two points is 7.211

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2 years ago

Solve for y<br> x+y= -15

Illusion [34]

X + y = -15. Subtract x from both sides.

y = -x - 15. This is as far as we can go with the provided information.

5 0

3 years ago

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The distribution of IQ scores can be modeled by a normal distribution with mean 100 and standard deviation 15.

evablogger [386]

Answer:

4.4% of the population with IQ between 120 and 125.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ scores is a bell shaped distribution that is a normal distribution.

a) Let X be a person's IQ score.

Then, density functions for IQ scores is given by:

$P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{z^2}{2}}\\\\\text{where,}\\\\z = \frac{x-\mu}{\sigma}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-\mu)^2}{2\sigma^2}}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-100)^2}{450}}$

b) P(population with IQ between 120 and 125.)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

$P(120 \leq x \leq 125) = P(\displaystyle\frac{120 - 100}{15} \leq z \leq \displaystyle\frac{125-100}{15}) = P(1.33 \leq z \leq 1.66)\\\\= P(z \leq 1.66) - P(z < 1.33)\\= 0.952 - 0.908 = 0.044 = 4.4\%$

$P(120 \leq x \leq 125) = 4.4\%$

6 0

3 years ago

Please help ASAP! thank you

AysviL [449]

Answer:

Step-by-step explanation:

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3 years ago