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Nataly [62]
4 years ago
14

Evaluate ³√-8 please help.

Mathematics
2 answers:
egoroff_w [7]4 years ago
5 0

-8=-2^3 so the answer is -2.

MrRa [10]4 years ago
5 0

-8 to the 1/3 power is -2

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If h = 3.7 then what is 0.8 + h?
Gnoma [55]
H=3.7
Then 0.8+h=0.8+3.7
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4 0
4 years ago
Find the cdf F(x) associated with each of the following probability density functions. Sketch the graphs of f(x) and F(x).
wolverine [178]

Answer:

See steps below

Step-by-step explanation:

a)

\bf f(x)=3(1-x)^2\;(0

\bf F(x)=\int_{0}^{x}f(t)dt=\int_{0}^{x}3(1-t)^2dt=3\int_{0}^{x}(1-t)^2=1-(1-x)^3

The cdf associated with f is

\bf \boxed{F(x)=1-(1-x)^3} for 0<x<1

<h3>See picture 1 </h3>

The median is a point x such that

F(x) = ½

so, the median is

\bf 1-(1-x)^3=1/2\rightarrow (1-x)^3=1/2\rightarrow \boxed{x=1-\sqrt[3]{2}}

The 25th percentile equals the 1st quartile and is a point x such

F(x) = ¼

and the 25th percentile is

\bf 1-(1-x)^3=1/4\rightarrow (1-x)^3=3/4\rightarrow \boxed{x=1-\sqrt[3]{3/4}}

b)

\bf f(x)=\frac{1}{x^2}\;(1

\bf F(x)=\int_{1}^{x}f(t)dt=\int_{1}^{x}\frac{dt}{t^2}=1-\frac{1}{x}

The cdf associated with f is

\bf \boxed{F(x)=1-\frac{1}{x}} for x>1

<h3>See picture 2 </h3>

The median is

\bf 1-\frac{1}{x}=\frac{1}{2}\rightarrow \boxed{x=2}

The 25th percentile is  

\bf 1-\frac{1}{x}=\frac{1}{4}\rightarrow \boxed{x=4/3}

c)

f(x) = 1/3 for 0<x<1 or 2<x<4

\bf F(x)=\int_{0}^{x}\frac{dt}{3}=\frac{x}{3}\;(0

\bf F(x)=\frac{1}{3}+\int_{2}^{x}\frac{dt}{3}=\frac{1}{3}+\frac{x-2}{3}=\frac{x-1}{3}\;(2

The cdf associated with f is

\bf F(x)=\frac{x}{3} for 0<x<1

\bf F(x)=\frac{x-1}{3} for 2<x<4

<h3>See picture 3 </h3>

The median is

\bf \frac{x-1}{3}=1/2\rightarrow x=1+3/2\rightarrow \boxed{x=5/2}

The 25th percentile is  

\bf \frac{x}{3}=1/4\rightarrow \boxed{x=3/4}

4 0
4 years ago
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yuradex [85]
X- 5>25 if you need to write out the equation
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3 years ago
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find the leftover by subtracting 3/16 from 9/16

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