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Nataly [62]
4 years ago
14

Evaluate ³√-8 please help.

Mathematics
2 answers:
egoroff_w [7]4 years ago
5 0

-8=-2^3 so the answer is -2.

MrRa [10]4 years ago
5 0

-8 to the 1/3 power is -2

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4.00....................
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Given: 5x + 3 &gt; 4x + 7.<br><br><br><br> Choose the graph of the solution set.
Natali5045456 [20]

Answer:

5x+3>4x+7

-4x      -4x

x+3>7

-3     -3

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so the answer will be the second

Step-by-step explanation:

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What's bigger 1.60 or 1.6
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What is the result of subtracting the second equation from the first? \begin{aligned} -7x-y &amp;= 0 \\\\ 7x+8y &amp;= -6 \end{a
Kitty [74]

Answer:

-14x-9y=6

Step-by-step explanation:

We are given with two equations

first equation is  -7x-y=0

second equation is

7x+8y=-6

we find the result of subtracting two equation

subtract the second equation from the first, so

first equation - second equation, multiply second equation by -1  and then add it with first equation

-7x-y=0

-7x-8y=+6

Now add both equations, we get

-14x-9y=6

3 0
3 years ago
Misaka solved the radical equation x – 3 = square root of 4x-7 but did not check her solutions. (x – 3)2 = square root of 4x-7^2
Minchanka [31]

Answer:

x=8 is a true solution of the radical equation

Step-by-step explanation:

we have

x-3=\sqrt{4x-7}

Solve for x

squared both sides

(x-3)^{2}=4x-7\\\\x^{2}-6x+9=4x-7\\\\ x^{2}-10x+16=0

Convert to factored form

x^{2}-10x+16=(x-2)(x-8)

The solutions are x=2 and x=8

<u><em>Verify the solutions</em></u>

For x=2

Substitute in the original equation

2-3=\sqrt{4(2)-7}

-1=1 ----> is not true

therefore

x=2 is not a true solution of the radical equation

For x=8

Substitute in the original equation

8-3=\sqrt{4(8)-7}

5=5 ----> is true

therefore

x=8 is a true solution of the radical equation

3 0
4 years ago
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