12x^2 = 4/3
x^2 = 1/9
x= +/- 1/3
Answer:
23.9894949495cm is the depth of the container.
Step-by-step explanation:
Cylindrical container:
height: 28
radius: 9 (or 18/2)
pi * 9² = 254.4690049408
254.4690049408 * 28 = 7,125.1321383424 cm²
cylidrical container area: 7,125.1321383424cm²
Container:
length: 27cm
width: 11cm
27 * 11 = 297
7,125.1321383424 / 297 = 23.9894949495cm
I assume that the container with rectangular base is precisely full when tou pour the water into it.
And that your question was how deep the container was.
When solving system equations, we can use substitution method or elimination. Today I'm using substitution method.
First name the 2 equations.
3x + y = 3 (1)
x + y = 2 (2)
Now pick one equation and express one algebra in forms of the other.
From (2),
x = 2 - y (3)
Now substitute (3) into (1),
3(2-y) + y = 3
6 - 3y + y = 3
6 - 2y = 3
6 - 3 = 2y
y = 1.5
Now substitute y = 1.5 into (2)
x + 1. 5 = 2
x = 2 - 1.5
x = 0.5
Therefore the answer is x = 0.5 and y = 1.5
Ok
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=

a=-0.04
b=8.3
c=4.3
x=

x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m