Solve 2 + 1/6y = 3x + 4 for y.

Mathematics

1 answer:

ruslelena [56]3 years ago

5 0

The answer is y=18x+12

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The Table below is a data set that lists how many pairs of shoes are owned by some of your classmates.

Pani-rosa [81]

Answer:

7.5

Step-by-step explanation:

To find the median, first order the numbers from least to greatest:

2, 4, 5, 7, 8, 8, 10, 12

Then, find the middle number (number in the middle):

There are 2 middle numbers. 7 and 8.

Because there are 2 numbers, we need to find the average. If there was only one number, that would be the median.

To find the average, add 7 and 8. Then, divide the sum by 2 because there are 2 numbers;

7 + 8 = 15

15 / 2 = 7.5

Have a nice day!

8 0

3 years ago

Criminal investigators use biometric matching for fingerprint recognition, facial recognition, and iris recognition. When matchi

Art [367]

Answer:

It is not a Type I error neither a Type II error.

Step-by-step explanation:

Let $\mu$ be the true mean match score. The null hypothesis is $H_{0}: \mu = 80$ and the alternative hypothesis is $H_{1}: \mu > 80$ (upper-tail alternative). When the test shows that the mean match score is more than 80 when actually is equal to 80 a Type I error is made. On the other hand, when the test shows that the mean match score is equal to 80 when actually is more than 80 a type II error is made. Therefore, when the test shows that the mean match score is more than 80 when the person does not actually have a fingerprint match, does not correspond to a Type I error neither to a Type II error.

6 0

3 years ago

Pleaseeeeeeeeeeee

Karo-lina-s [1.5K]

$\text{The scientific notation:}\\\\a\times10^n\\\\1\leq a$

$a.\\(5\times10^3)\times(3.5\times10^{-1})=(5\times3.5)\times(10^3\times10^{-1})\\\\=15.75\times10^{3+(-1)}=15.75\times10^2=1.575\times10\times10^2\\\\=1.575\times10^{1+2}=\boxed{1.575\times10^3}$

$b.\\(8\times10^2)\div(4\times10^3)=(8\div4)\times(10^2\div10^3)=2\times10^{2-3}\\\\=\boxed{2\times10^{-1}}$

$c.\\(6\times10^{-3})^2=6^2\times(10^{-3})^2=36\times10^{-3\cdot2}=36\times10^{-6}=3.6\times10\times10^{-6}\\\\=3.6\times10^{1+(-6)}=\boxed{3.6\times10^{-5}}$