Solve 2 + 1/6y = 3x + 4 for y.

What is 47/20 as a decimal

Whitepunk [10]

$x=decimal
 \\ 47 \ divided \ by \ 20 \ is \ 2.35
 \\ x=2.35
 \\$

5 0

3 years ago

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Which graph shows the solution set for |x - 3| < 4?

ikadub [295]

Answer:

see below

Step-by-step explanation:

|x - 3| < 4

To remove the absolute values, we need to make two inequalities, one positive and one negative

x-3 < 4 and x-3 > -4

Add 3 to each side

x-3+3<4+3 and x-3+3 > -4+3

x<7 and x >-1

-1 <x <7

4 0

3 years ago

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Milli plans to rent a room for her birthday party for $40. The catering charge is $12 per person but there is no charge for Mili

Naddik [55]

5 people + Milli As 100-40=60 Therefore, 60/12=5

6 0

3 years ago

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Together, Kyle and Tyler traveled 425 miles to the beach. If Kyle traveled 240 miles, how far did Tyler travel? A) 2x = 425 B) x

Snezhnost [94]

Answer:

the answer is x=185

Step-by-step explanation:

x+240=425

-240 -240

x= 185

3 0

3 years ago

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Please help very urgent

Alik [6]

Answer:

32, 16, 8, 4, 2, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

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We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

2 years ago

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