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Leokris [45]
2 years ago
11

A stadium has 47,000 seats. Seats sell for $42 in Section A, $36 in Section B, and $30 in Section C. The number of seats in Sect

ion A equals the total number of seats in Sections B and C. Suppose the stadium takes in $1,779,000 from each sold-out event. How many seats does each section hold?​
Mathematics
1 answer:
kupik [55]2 years ago
5 0

Answer:

section A holds 23,500 Section B holds 11,750 And Section C holds 11,750

Step-by-step explanation:

Section A is half of the stadium so divide 47,00 by 2 you get 23,300 so that is Section A than b and c are the other half for divide 23,500 by 2 and you get 11,750

You might be interested in
Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

\bar {x}_1 = 13.5

\bar {x}_2 = 12

σ₁ = 2.5

σ₂ = 1.5

We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

8 0
3 years ago
Which of the following statements is false?
kramer

Option D

The sum of two irrational numbers is always rational is false statement

<em><u>Solution:</u></em>

<h3><u>The sum of two rational numbers is always rational</u></h3>

"The sum of two rational numbers is rational."

So, adding two rationals is the same as adding two such fractions, which will result in another fraction of this same form since integers are closed under addition and multiplication. Thus, adding two rational numbers produces another rational number.

For example:

\frac{1}{4} + \frac{1}{5} = \frac{9}{20}

rational number + rational number = rational number

Hence this statement is true

<h3><u>The product of a non zero rational number and an irrational number is always irrational</u></h3>

If you multiply any irrational number by the rational number zero, the result will be zero, which is rational.

Any other situation, however, of a rational times an irrational will be irrational.

A better statement would be: "The product of a non-zero rational number and an irrational number is irrational."

So this statement is correct

<h3><u>The product of two rational numbers is always rational</u></h3>

The product of two rational numbers is always rational.

A number is said to be a rational number if it is of the form p/q,where p and q are integers and q ≠ 0

Any integer is a rational number because it can be written in p/q form.

Hence it is clear that product of two rational numbers is always rational.

So this statement is correct

<h3><u>The sum of two irrational numbers is always rational</u></h3>

"The sum of two irrational numbers is SOMETIMES irrational."

The sum of two irrational numbers, in some cases, will be irrational. However, if the irrational parts of the numbers have a zero sum (cancel each other out), the sum will be rational.

Thus this statement is false

5 0
3 years ago
Simplyify t^12/t^6 *PLEASE HELP*
Julli [10]

Answer:

C

Step-by-step explanation:

In division when bases are same you do top exponent minus bottom exponent.

So here you do t^(12-6) which is t^6.

3 0
3 years ago
Help me get the possible point, no link or virus please.
matrenka [14]

Answer:

k(x) = -40

i(x) = -15

n(x) = 71

d(x) = 17

Step-by-step explanation:

This is exactly the same deal as the most recent question you asked.

"Evaluate each function for x = 8". In other words, this is saying, calculate the result for each function, replace x with 8. So, that means for every function, you are going to replace x with 8.

k(x) = -5x turns into k(x) = -5(8)

Then you just solve, -5(8) = -40

Since I have answered this question similarly, I ask that you go back to the answer and detailed explanation I gave you earlier.

6 0
2 years ago
Help plz who ever helps they are nice
slava [35]
Im mean I’d be down to help
4 0
2 years ago
Read 2 more answers
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