<span>In
the desert food web shown below, which of the following best describes
the transfer of energy between the lubber grasshopper and the kangaroo
rat?
</span>
<span>C) About 10 percent of the kangaroo rat's energy transfers to the lubber grasshopper.
</span>
The answer here is ATP.
ATP is used in the first step of glycolysis to convert glucose into glucose-6-phosphate (that's where the phosphate comes from).
Double fertilization-plants with seeds (flowering plants), two male gametes joining with female gametophyte
Gametophyte generation-both (haploid, sexual stage stage-gametophyte, and the diploid stage that produces spores – sporophyte)
Endosperm formed-plants with seed because it is a tissue formed inside the seed which surrounds the embryo and provides nutrition
Mitosis-both (mitosis occurres in spores)
Spores develop into gametophytes-both but, in seedless plants sporophyte produces spores that will develop into a new organism (multicellular gametophyte) using mitosis, while spores of seed plants are produced internally and develop into more complex structures.
Idk bro sorry but I’m only in the 7th grade and don’t take biology
The magnitude of the work done by the electric field of the membrane is <u>W = 1.28 × 10⁻²⁰ Joules</u>.
We start with the necessity to take into account a value for the voltage present there in order to solve this problem by first considering that the membranes have two layers, one internal and one external, each responsible for producing a potential difference between the two levels.
As a result, in order to find a solution, it is necessary to take into account the potential difference between the two surfaces. In this instance, we'll assume a particular value for the load, but the recipient is free to substitute a different value if they prefer.
The product of the potential difference and the charge is used to define the work that an electric field performs. The charge of the potassium ion will be equal to that of its electron, so,
q = 1.6 × 10⁻¹⁹ Coulombs
Then the Work would be:
W = Vq
Here,
v = Potential difference
q = Charge
The 80mV potential difference we will have is quantified as follows:
W = (80mV (1V/1000mV))( 1.6 × 10⁻¹⁹ C)
W = 1.28 × 10⁻²⁰ Joules is the amount of work that the membrane's electric field has produced.
Find more on work done at : brainly.com/question/25573309
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