The experimental probability that only 2 of 4 children in a family are boys is <u>50%</u>.
<h3>What is experimental probability?</h3>
Experimental probability refers to the chance of an expected success being achieved in a series of experiments conducted.
Experimental probability is the number of times that the expected success occurs as a fraction of the total number of times the experiment was conducted.
Like all probabilities, the experimental probability is based on the likelihood that what the experimenter expects is achieved.
Expected number of boys = 2
The number of children in the family = 4
Experimental probability = 50% (2/4 x 100)
Thus, we can conclude, based on the experimental probability, that <u>50%</u> (or 2) of the 4 children in the family are boys.
Learn more about experimental probabilities at brainly.com/question/8652467
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Answer:
y = 6
Step-by-step explanation:
6 * y * 4 = 2 * 72
y = 2 * 72/24 = 6
Answer:
You can put it into 3 forms:
Exact form: 19/8
Decimal Form: 2.375 (Rounded=2.38)
Mixed Number Form: 2 3/8
Answer:
B (cylinder)
Step-by-step explanation:
Two <u>circular</u> bases which are parallel and congruent :
This basically means that the shape contains a circular base (supposedly the bottom), but since it has two bases, its on the top and the bottom. Because it's congruent, the bases are both equal in shape and size. It is also parallel as well, in which the bases have the same distance between them.
The cube doesn't have any circular bases.
The sphere doesn't have any faces, nor edges.
A cone has a circular base, but it doesn't have two.
A cylinder has two circular bases, as well as they are parallel and congruent.
So, your answer is B (cylinder).
Hope this helped !
Simplify each term<span>.</span>
Simplify <span>3log(x)</span><span> by moving </span>3<span> inside the </span>logarithm<span>.
</span><span>log(<span>x^3</span>)+2log(y−1)−5log(x)</span><span>
</span>
Simplify <span>2log(y−1)</span><span> by moving </span>2<span> inside the </span>logarithm<span>.
</span><span>log(<span>x^3</span>)+log((y−1<span>)^2</span>)−5log(x)</span><span>
</span>
Rewrite <span>(y−1<span>)^2</span></span><span> as </span><span><span>(y−1)(y−1)</span>.</span><span>
</span><span>log(<span>x^3</span>)+log((y−1)(y−1))−5log(x)</span><span>
</span>
Expand <span>(y−1)(y−1)</span><span> using the </span>FOIL<span> Method.
</span><span>log(<span>x^3</span>)+log(y(y)+y(−1)−1(y)−1(−1))−5log(x)</span><span>
</span>
Simplify each term<span>.
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>x^<span>−5</span></span>)</span><span>
</span>Remove the negative exponent<span> by rewriting </span><span>x^<span>−5</span></span><span> as </span><span><span>1/<span>x^5</span></span>.</span><span>
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>1/<span>x^5</span></span>)</span><span>
</span>
Combine<span> logs to get </span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))
</span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))+log(<span>1/<span>x^5</span></span>)
</span>Combine<span> logs to get </span><span>log(<span><span><span>x^3</span>(<span>y^2</span>−2y+1)/</span><span>x^5</span></span>)</span><span>
</span>log(x^3(y^2−2y+1)/x^5)
Cancel <span>x^3</span><span> in the </span>numerator<span> and </span>denominator<span>.
</span><span>log(<span><span><span>y^2</span>−2y+1/</span><span>x^2</span></span>)</span><span>
</span>Rewrite 1<span> as </span><span><span>1^2</span>.</span>
<span><span>y^2</span>−2y+<span>1^2/</span></span><span>x^2</span>
Factor<span> by </span>perfect square<span> rule.
</span><span>(y−1<span>)^2/</span></span><span>x^2</span>
Replace into larger expression<span>.
</span>
<span>log(<span><span>(y−1<span>)^2/</span></span><span>x^2</span></span>)</span>
