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rewona [7]
3 years ago
6

If △ABC≅△XYZ, SELECT ALL THE CORRECT STATEMENTS. There will be MORE than one right answer.

Mathematics
2 answers:
adoni [48]3 years ago
4 0

AYE i just did the quiz i got you GIRL it's the first one, third and the last one


hjlf3 years ago
4 0

Answer:

AB=XY

BC=YZ

CA=ZX

Step-by-step explanation:

we know that

If two figures are congruent, then its corresponding sides will be congruent

so

in this problem we have

AB=XY

BC=YZ

CA=ZX



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9. Given the point (6,-8) values of the six trig function.
lozanna [386]

Answer:

Here's what I get.

Step-by-step explanation:

9. (6, -8)

The reference angle θ is in the fourth quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100

OB = √100 = 10  

\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}

10. cot θ = -(√3)/2

The reference angle θ is in the second quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7

OB = √7

\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}

3 0
3 years ago
Find the sum of the given polynomials. 5m + 2n, n - 3m, and 7 - 3n
Nataly_w [17]
5m+2n+n-3m+7-3n =2m +7
7 0
3 years ago
PLEASE PLEASE PLEASE HELP ILL GIVE YOU BRAINLIST. PLEASE.
elena-s [515]

Answer:

X=36

Step-by-step explanation:

90-54=36

Right angle 90 subtract 54

The missing angle x is 36

6 0
3 years ago
PLEASE HELP (question is in picture)
HACTEHA [7]

Answer:

4*3=12

12*4=

3*3=9

9*2=18

18+48=66

Step-by-step explanation:

8 0
3 years ago
Write a ratio, in the simplest form and a percent for the shaded area (there's a 5x4 box and 6 cubes are shaded)
Alexxandr [17]

Answer:

\%Percent = 30 \%

Step-by-step explanation:

Given

Shaded = 6\ cubes

Box = 5\ x\ 4

Required

Determine the percentage of the shaded cubes

First, we calculate the number of boxes:

Box = 5\ x\ 4

Express as multiplication

Box = 5\ *\ 4

Box = 20

This implies that there are 20 cubes in the box.

The percentage of the shaded cubes is:

\%Percent = \frac{Shaded}{Box} * 100\%

\%Percent = \frac{6}{20} * 100\%

\%Percent = \frac{6* 100}{20} \%

\%Percent = \frac{600}{20} \%

\%Percent = 30 \%

<em>30% were shaded</em>

5 0
2 years ago
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