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shtirl [24]
3 years ago
14

A triangle has vertices A(1, 1), B(2, 4), and C(4, 2). Line p is parallel to side AB and contains point C.

Mathematics
1 answer:
kenny6666 [7]3 years ago
4 0

Answer:

p:y = 3x-10

Step-by-step explanation:

We are given the following in the question:

A(1, 1), B(2, 4), C(4, 2)

i) Slope of AB

A(1, 1), B(2, 4)\\\\m = \dfrac{y_2-y_1}{x_2-x_1}\\\\m = \dfrac{4-1}{2-1}=3

Thus, slope of AB is 3.

ii) Point slope form

The point slope form of a line can be written as:

y - y_1 = m(x - x_1)

The point intercept form of line can be written as:

y = mx + c

The line is parallel to AB and contains point C(4, 2). Since line p is parallel to AB, line p will have the same slope as line AB

Putting values, we get,

y - 2 = 3(x-4)\\y = 3x-12+2\\y = 3x-10

which is the required slope intercept equation of line p.

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