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3 years ago

Difference of squares: What is x^2-9=0? please help me....

Mathematics

2 answers:

Cloud [144]3 years ago

8 0

Answer:

3 or -3

Step-by-step explanation:

You need to factor it to be able to find the solution.

x^2-9=0

(x+3)(x-3)=0 You now need to find 'each' zero, because if one parenthesis equals 0, then you are multiplying the rest of the equation by 0 which will equal 0.

x+3=0 Subtract three

x= -3

x-3=0 Add three

x= 3

x^2-9 will equal 0 when x is either +3 or -3

nevsk [136]3 years ago

8 0

Answer:

x=3 x=-3

Step-by-step explanation:

x^2-9=0

We know this is the difference of squares

a^2 - b^2 = (a-b) (a+b)

(x-3)(x+3) =0

Using the zero product property

x-3 =0 x+3 =0

x=3 x=-3

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kolezko [41]

Answer:

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Step-by-step explanation:

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So the equation of the perpendicular line is y = -4x - 4 (Answer)

It is always a good idea to plot these graphs and see if they fit the data provided

The attached plot shows the two graphs and you can see they are perpendicular to each other and the perpendicular line(the answer) passes through point (-3,8)

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Difference of squares: What is x^2-9=0? please help me....​

Difference of squares: What is x^2-9=0? please help me....