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3 years ago

Difference of squares: What is x^2-9=0? please help me....

Mathematics

2 answers:

Cloud [144]3 years ago

8 0

Answer:

3 or -3

Step-by-step explanation:

You need to factor it to be able to find the solution.

x^2-9=0

(x+3)(x-3)=0 You now need to find 'each' zero, because if one parenthesis equals 0, then you are multiplying the rest of the equation by 0 which will equal 0.

x+3=0 Subtract three

x= -3

x-3=0 Add three

x= 3

x^2-9 will equal 0 when x is either +3 or -3

nevsk [136]3 years ago

8 0

Answer:

x=3 x=-3

Step-by-step explanation:

x^2-9=0

We know this is the difference of squares

a^2 - b^2 = (a-b) (a+b)

(x-3)(x+3) =0

Using the zero product property

x-3 =0 x+3 =0

x=3 x=-3

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3 years ago

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Which expression is equivalent to the product of p+7/3 and 6/p , where p is not equal to 0?

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Answer:

$\frac{(6p+14)}{p}$

Step-by-step explanation:

$(p+\frac{7}{3})(\frac{6}{p})$

Making denominator same in first bracket we get

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2 years ago

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Consider the following equations and name the property of equality used to solve for the variable.

Anestetic [448]

Answer:

Subtraction property ; x = 3.25

Division property ; - 6

multiplication property ; - 125

Addition property ; 13

Step-by-step explanation:

A.)

x + 3.75 = 7

Using the subtraction property : subtract 3.75 from both sides

x + 3.75 - 3.75 = 7 - 3.75

x = 3.25

B. )

–3b = 18

According to the division property :

Divide both sides by - 3

-3b / - 3 = 18 / - 3

b = - 6

C.)

m/5 = - 25

Using the multiplication property :

m/5 * 5 = - 25 * 5

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D.)

m – 4 = 9

Using the addition property :

Add 4 to both sides :

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What is the midpoint of the segment shown below?

kolbaska11 [484]

The midpoint of the segment is (-15/2, -15/2)

<h3>How to determine the midpoint?</h3>

The complete question is in the attached image

The points are given as:

(-8, -7) and (-7, -8)

The midpoint is calculated as:

(x,y) = 1/2 * (x1 + x2, y1 + y2)

So, we have:

(x,y) = 1/2 * (-8 - 7, -7 - 8)

Evaluate the difference

(x,y) = 1/2 * (-15, -15)

Evaluate the product

(x,y) = (-15/2, -15/2)

Hence, the midpoint of the segment is (-15/2, -15/2)

Difference of squares: What is x^2-9=0? please help me....​

Difference of squares: What is x^2-9=0? please help me....