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3 years ago

When converted to a household measurement, 9 kilograms is approximately equal to a

Mathematics

2 answers:

liubo4ka [24]3 years ago

6 0

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

a_sh-v [17]3 years ago

5 0

Abt 317.4 oz or 19.4 lb

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Plz help me get the right answer to these

Citrus2011 [14]

- $b^{4}$ + 6 $b^{3}$

divide each term on the numerator by 7b

= - 7 $b^{5}$ / 7b + 42 $b^{4}$ / 7b

= - $b^{4}$ + 6 $b^{3}$

4 0

3 years ago

Read 2 more answers

Assembly Department $280,000

DIA [1.3K]

<h2><u>Answer :-</u></h2>

A. Commercial 540

Residential 360

B. Commercial 585

Residential 390

<h2><u>Explanation :-</u></h2>

a) Calculation to Determine the per-unit factory overhead allocated to the commercial and residential motors .

First step is to calculate the Plantwide overhead rate using this formula

Plantwide overhead rate =Estimated overhead /Estimated machine hours

Let plug in the formula

Plantwide overhead rate = 1080000/9000

Plantwide overhead rate = $ 120 per MH

Now let Determine the per-unit factory overhead allocated to the commercial and residential motors

Using this formula

Per -unit factory overhead allocated=Actual MH per unit *Plantwide overhead rate

Let plug in the formula

Per -unit factory overhead allocated to COMMERCIAL=4.5 dmh*120

Per -unit factory overhead allocated to COMMERCIAL=540

Per -unit factory overhead allocated to RESIDENTIAL=3.0 dmh*120

Per -unit factory overhead allocated to RESIDENTIAL=360

Therefore the per-unit factory overhead allocated to the commercial and residential motors under the single plantwide factory overhead rate method will be:

Commercial 540

Residential 360

b. Calculation to Determine the per-unit factory overhead allocated to the commercial and residential motors

First step is to calculate the Departmental overhead rate

ASSEMBLY TESTING

Estimated overhead 280,000 800,000

÷Estimated machine hours each department 4,000 5,000

=Departmental overhead rate 70 160

Now calculation the per-unit factory overhead allocated to the commercial and residential motors

COMMERCIAL RESIDENTIAL

Assembly 1.5 dmh*70=105 1.0 dmh*70=70

Testing 3.0*160= 480 2.0*160= 320

Per -unit factory overhead allocated 585 390

(105+480=585)

(70+320=390)

Therefore the per-unit factory overhead allocated to the commercial and residential motors under the multiple production department factory overhead rate method will be:

Commercial 585

Residential 390

7 0

3 years ago

Several terms of a sequence {an}n=1 infinity are given. A. Find the next two terms of the sequence. B. Find a recurrence relatio

s344n2d4d5 [400]

Answer:

A) $\frac{1}{1024},\frac{1}{4096}$

B) $\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.$

C) $\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...$

Step-by-step explanation:

1) Incomplete question. So completing the several terms: $\left \{a_{n}\right \}_{n=1}^{\infty}=\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},... \right \}$

We can realize this a Geometric sequence, with the ratio equal to:

$q=\frac{1}{4}$

A) To find the next two terms of this sequence, simply follow multiplying the 5th term by the ratio (q):

$\frac{1}{256}*\mathbf{\frac{1}{4}}=\frac{1}{1024}\\\\\frac{1}{1024}*\mathbf{\frac{1}{4}}=\frac{1}{4096}\\\\\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},\mathbf{\frac{1}{1024},\frac{1}{4096}}\right \}$