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DanielleElmas [232]
1 year ago
10

Task 13: are the expressions equivalent? Simplify to prove, if the two expressions are not equal write the correct equivalence.

Mathematics
1 answer:
yarga [219]1 year ago
8 0

Answer:

#5: Equivalent

#6: Not Equivalent

1. 3x+6

2. 4y-4

3. x²+6x

4. xy+4x

5. 3x²+3xy-3x

Step-by-step explanation:

for #6 the equivalent: 2x(x+3)= 2x²+6x

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Consider the tables created using an initial investment of $1,000 and quarterly compounding of interest.
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Answer:

(d)  The functions are not inverses because for each ordered pair (x, y) for one function, there is no corresponding ordered pair (y, x) for the other function.

Step-by-step explanation:

If functions are represented by a table of ordered pairs, their inverse function is the set of ordered pairs with the x- and y-values swapped.

Here, for (x, y) = (0.75, 1038.18), the pair from the other table that begins to correspond is (y, x) = (0.75, 1057.81). These reversed pairs are not the same, so the functions are not inverses of each other.

_____

<em>Comment on the tables</em>

Table A is for a 5-year investment; table B is for a 7.5 year investment. They cannot be inverses of each other.

8 0
4 years ago
Read 2 more answers
Start with the following statement: Vertical angles are congruent. a.State the conditional and three other forms of the statemen
WARRIOR [948]
There are three kinds of statement that we could construct base on the given where as Vertical angels are congruent. First is converse: If angle 1 is 90 degree then angle 2 is 90. Second is Inverse: If angle 2 is not 90 then angle 1 is not. Third is Contrapositive: If angle 2 is not 90 then angle 1 is not 90 also.
8 0
3 years ago
Pls Help! Very Easy! 10 points! Brainliest if you are correct!
SSSSS [86.1K]
We can see that the 33 degrees corresponds to angle A (parallel lines) meaning they’re equal.
This means that 33 + 2x = 5x (5x is the exterior angle, so the other two interior angles’ sum must equal to it)
3x = 33
x = 11
3 0
3 years ago
Divide the combinations.<br><br> 60C3 / 15C3
Mariulka [41]
I hope you know what '!' means
2!=2
3!=6
4!=24
basicalkly times every natural number including and before that number


nCr=\frac{n!}{r!(n-r)!}
so
\frac{60C3}{15C3}=
\frac{ \frac{60!}{3!(60-3)!} }{ \frac{15!}{3!(15-3)!} }=
( \frac{60!}{3!(60-3)!})(\frac{3!(15-3)!}{15!})=
( \frac{60!}{3!(57)!})(\frac{3!(12)!}{15!})=
\frac{(60!)(3!)(12!)}{(3!)(57!)(15!)}=
\frac{(60!)(12!)}{(57!)(15!)}=
\frac{(60!)}{(57!)(15)(14)(13)}=
\frac{(60)(59)(58)}{(15)(14)(13)}=
\frac{(30)(59)(58)}{(15)(7)(13)}=
\frac{(6)(59)(58)}{(3)(7)(13)}=
\frac{6844}{91}
4 0
4 years ago
Read 2 more answers
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natali 33 [55]
If M <span>is the midpoint of AB then AB = 2AM

8x - 6 = 2(3x + 3)
8x - 6 = 6x + 6
8x - 6x = 6 + 6
2x = 12
x = 12/2
x = 6

AM = 3x + 3 = 3*6 + 3 = 18 + 3 = 21 units
</span>
6 0
4 years ago
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