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2 years ago

C increased by 8 can I get help

Mathematics

1 answer:

Brums [2.3K]2 years ago

3 0

Answer:

the answer based on the information provided is c + 8

Step-by-step explanation:

8 added to C is c + 8, since they are unlike terms

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Use the 95% rule and the fact that the summary statistics come from a distribution that is symmetric and bell-shaped to find an

Nonamiya [84]

Answer:

Intervals = (1,064) , (1,036)

Step-by-step explanation:

Given:

Use 95% method

Mean = 1,050

Standard deviation = 7

Find:

Intervals.

Computation:

95% method.

⇒ Intervals = Mean ± 2(Standard deviation)

⇒ Intervals = 1,050 ± 2(7)

⇒Intervals = 1,050 ± 14

⇒ Intervals = (1,050 + 14) , (1,050 - 14)

⇒ Intervals = (1,064) , (1,036)

4 0

2 years ago

What is it??????????

spayn [35]

Hey! :)

Some things to note: When you bring a exponent to the numerator, you make it negative.

When you put an exponent to another exponent, you multiply the exponents together.

$(\frac{3x^2y^5}{x^6y^2} )^4\\\frac{81x^8y^{20}}{x^{24}y^8}\\81x^8x^{-24}y^{20}y^{-8}\\\frac{81y^{12}}{x^{16}}$

so that is your answer, please let me know if you need more of an explanation. :)

8 0

3 years ago

Hwllppooppppoopppppppp

babunello [35]

Answer:

Step-by-step explanation:

because they are in large sizes but small amount of time

5 0

2 years ago

Read 2 more answers

What is the midpoint of (-2,3) and (10,3) *simple answer please

Allushta [10]

The "midpoint formula" is the same as the "average formula:"

x-coordinate of the midpoint = average of -2 and 10:

= (-2 + 10) / 2 = 4

y-coordinate of the midpoint = average of 3 and 3:

= (3+3) / 2 = 3

Thus, the midpoint of the given line segment is (4,3).

5 0

3 years ago

Suppose F⃗ (x,y)=(x+3)i⃗ +(6y+3)j⃗ . Use the fundamental theorem of line integrals to calculate the following.

Scorpion4ik [409]

In order to use the fundamental theorem of line integrals, you need to find a scalar potential function - that is, a scalar function f(x, y) for which

grad f(x, y) = F(x, y)

This amounts to solving for f such that

∂f/dx = x + 3

∂f/∂y = 6y + 3

Integrating both sides of the first equation with respect to x gives

f = 1/2 x ^2 + 3x + g(y)

Differentiating with respect to y gives

∂f/∂y = dg/dy = 6y + 3

Solving for g gives

g = ∫ (6y + 3) dy = 3y ^2 + 3y + C

and hence

f(x, y) = 1/2 x ^2 + 3x + 3y ^2 + 3y + C

(a) By the fundamental theorem, the integral of F along any path starting at the point P (1, 0) and ending at Q (3, 3) is

∫ F(x, y) • dr = f (3, 3) - f (1, 0) = 99/2 - 7/2 = 46

(b) Now we're talking about a closed path, so the integral is simply 0. We can verify this by checking the integral over the origin-containing paths:

• From the origin to P :

∫ F(x, y) • dr = f (1, 0) - f (0, 0) = 7/2 - 0 = 7/2

• From Q back to the origin:

∫ F(x, y) • dr = f (0, 0) - f (3, 3) = 0 - 99/2 = -99/2

Then the total integral is 7/2 + 46 - 99/2 = 0, as expected.

6 0

3 years ago