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Molodets [167]
3 years ago
8

Samuel took an antique clock that his grandfather had purchased, to be appraised. The appraiser evaluated the current price of t

he clock to be $400 and stated that the value will continue to increase at 2% per year.
Which of the following graphs shows the value of the antique clock, y, in dollars, after x years?

Mathematics
1 answer:
andrew11 [14]3 years ago
6 0
This is an exponential growth problem. Exponential growth can be expressed mathematically in the following way: 
y=a (1+r)^{t}.
Parameter a presents initial amount.
Parameter r is percentage increase. 
Parameter t is time.
An equation that would describe given problem is:
y=400 (1+0.02)^{t}
t is the time in years.
I attached the graph of this function.

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Edward owes his parents $20 for a new video
Galina-37 [17]

Answer:

it would take Edward 8 to pay back his debt

Step-by-step explanation:

every 2 days he pays his parents 5 bucks so because 5 times 4 equals 20 he would have to multiply the 4 by 2 and that gets you 8 days

3 0
3 years ago
1. Which fractions are equivalent to 10/14?
amm1812

Answer: 1. 5/7 , 20,28

               2. 5/11

               3. 10/3

               4. 13/4

              5. 60

              6. 36 mins

              7. 3/4 < 33/40

              8. 19/24 , 2/3 , 3/8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
1. Girl Scout Troop 321 started with 25 girls and at the end of the year party there were 31 girls. Gabby
Oksanka [162]

Answer: 24%

Step-by-step explanation:

Since we are informed that the Girl Scout Troop started with 25 girls and at the end of the year party there were 31 girls. The percentage change will be:

= (31 - 25) / 25 × 100

= 6/25 × 100

= 24%

The error that Gabby made was that she used 31 as the base. This is expressed below:

= 31 - 25) / 31 × 100

= 6/31 × 100

= 19.4%

3 0
3 years ago
Solve for y<br><br> -17x + 11y = 13
sveta [45]

Answer:

y=13/11+17x/11 (these are fractions)

Step-by-step explanation:

Move all terms that don't contain  

y  

to the right side and solve.

4 0
2 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
2 years ago
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