Distance, d, is directly proportional to the number of gallons of gas, g. Thus,
d α g
To turn alpha to equal sign, we insert a constant of proportionality, k.
d=kg
To find k, we use the given conditions.
476 = k (14)
k = 34
Therefore, the equation is,
d = 34g
and for travelling 578 miles,
578 = 34g
g = 17 gallons is needed.
Answer:
Given: Gables property Corp is leasing office buildings with an area of 
⇒ Area =
we can write this as:
Area = 
.....[1]
Use the identity formula:
then, by using this formula in [1] we have;
Area = 
or
Area = 
square units
Area of building = 
where l is the length and w is the width respectively;
⇒ 
units
Therefore, the possible length and width of the building is;
l = 7x+5 units
w = 7x+5 units
As we know that the Area of a square is equal to side times side . Since each side of a square is the same, it can simply be the length of one side squared.
Therefore, the possible shape of the building is Square.
<u><em>Answer: y=42</em></u>
Step-by-step explanation:
division property of equality is dividing both sides of an equation by the same non-zero number does not change the equation.
divide by -3 both sides of an equation.
-3(y-50)/-3=24/-3
simplify.
y-50=-8
add 50 both sides of an equation.
y-50+50=-8+50
simplify.
-8+50=42
50-8=42
42+8=50
y=42
Hope this helps!
Thanks!
Have a great day!
Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
then, Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9) (sec²Ф will have a negative value, because Ф is in the sec Ф=-5/3 third quadrant).
cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5
Therefore:
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2
Answer: tan (Ф/2)=-2; when tan (Ф)=4/3
It is 5 you just have to count
