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3 years ago

169/13 draw a quick picture with base ten blocks explain

Mathematics

1 answer:

Kitty [74]3 years ago

7 0

I wish i could show u how to work it out but just do it or work it out the same way as the fractional numbers.

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Question 13 (2 points)

Eddi Din [679]

Answer:

The math club has 22 students, and the art club has 34 students.

Step-by-step explanation:

Given that there are a total of 56 students between the art club and the math club, and that the art club has 12 more students than the math club, to determine how many students there are in each club, the following calculation must be performed:

X + X + 12 = 56

2X + 12 = 56

2X = 56 - 12

X = 44/2

X = 22

Thus, the math club has 22 students, and the art club has 34 students.

4 0

3 years ago

Change to a whole or mixed 17/5

krek1111 [17]

Answer:

3 2/5

Step-by-step explanation:

17/5

How many times does 5 go into 15

5*3 =15 3 times

17-15 =2 so there is 2 left over. This goes over the denominator

3 2/5

5 0

3 years ago

Read 2 more answers

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

3 years ago

4(v+7) = -6(3v-4) +8v<br>

xxTIMURxx [149]

Answer:

v=−27

Step-by-step explanation:

Since v is on the right side of the equation, switch the sides so it is on the left side of the equation.

−6(3v−4)+8v=4(v+7)

Simplify −6(3v−4)+8v

−10v+24=4(v+7)

Simplify 4(v+7).

−10v+24=4v+28

Move all terms containing v to the left side of the equation.

−14v+24=28

Move all terms not containing v to the right side of the equation.

−14v=4

Divide each term by −14 and simplify.

v=−27

The result can be shown in multiple forms.

Exact Form:

v=−27

6 0

3 years ago

Solve to get the value of h

iragen [17]

The answer to the question is h=64 degrees

4 0

3 years ago

Read 2 more answers