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Readme [11.4K]
3 years ago
5

A bag contains 10 red marbles, 7 green marbles. and 8 striped marbles. A marble is picked, then put back into bag. Find P(green

and striped).
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
8 0

G = number of green = 7

S = number of striped = 8

T = number total = 10+7+8 = 25

probability of picking green = P(G) = G/T = 7/25

probability of picking striped = P(S) = S/T = 8/25

P(green and striped) = P(G)*P(S)  ... events are independent

P(green and striped) = (7/25)*(8/25)

P(green and striped) = (7*8)/(25*25)

P(green and striped) = 56/625

P(green and striped) = 0.0896

--------------------------------

In summary, the answer as a fraction is 56/625

In decimal form, the answer is 0.0896

The value 0.0896 can be converted to percent form to get 8.96%

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If you remove the last digit (one’s place) from a 4-digit whole number, the resulting number is a factor of the 4-digit number.
shutvik [7]

Answer:

  900

Step-by-step explanation:

We assume that your 4-digit number must be in the range 1000 to 9999. Clearly, any number ending in zero will meet your requirement:

  1000/100 = 10

  3890/389 = 10

However, the requirement cannot be met when the 1s digit is other than zero.

__

For some 3-digit number N and some 1s digit x, the 4-digit number will be

  4-digit number: 10N+x

Dividing this by N will give ...

  (10N+x)/N = 10 remainder x

N will only be a factor of 10N+x when x=0.

So, there are 900 4-digit numbers that meet your requirement. They range from 1000 to 9990.

6 0
3 years ago
In a population of 10,000, there are 5000 nonsmokers, 2500 smokers of one pack or less per day, and 2500 smokers of more than on
Kazeer [188]

Answer:

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

Step-by-step explanation:

We have to write the transition matrix M for the population.

We have three states (nonsmokers, smokers of one pack and smokers of more than one pack), so we will have a 3x3 transition matrix.

We can write the transition matrix, in which the rows are the actual state and the columns are the future state.

- There is an 8% probability that a nonsmoker will begin smoking a pack or less per day, and a 2% probability that a nonsmoker will begin smoking more than a pack per day. <em>Then, the probability of staying in the same state is 90%.</em>

-  For smokers who smoke a pack or less per day, there is a 10% probability of quitting and a 10% probability of increasing to more than a pack per day. <em>Then, the probability of staying in the same state is 80%.</em>

- For smokers who smoke more than a pack per day, there is an 8% probability of quitting and a 10% probability of dropping to a pack or less per day. <em>Then, the probability of staying in the same state is 82%.</em>

<em />

The transition matrix becomes:

\begin{vmatrix} &NS&P1&PM\\NS&  0.90&0.08&0.02 \\  P1&0.10&0.80 &0.10 \\  PM& 0.08 &0.10&0.82 \end{vmatrix}

The actual state matrix is

\left[\begin{array}{ccc}5,000&2,500&2,500\end{array}\right]

We can calculate the next month state by multupling the actual state matrix and the transition matrix:

\left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4950&2650&2400\end{array}\right]

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

To calculate the the state for the second month, we us the state of the first of the month and multiply it one time by the transition matrix:

\left[\begin{array}{ccc}4950&2650&2400\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4912&2756&2332\end{array}\right]

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

If we repeat this multiplication 12 times from the actual state (or 10 times from the two-months state), we will get the state a year from now:

\left( \left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] \right)^{12} =\left[\begin{array}{ccc}4792.63&3005.44&2201.93\end{array}\right]

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

3 0
3 years ago
Please help!! i need this asap
kompoz [17]

I would help but I cannot read it.

3 0
3 years ago
Two cars leave towns 360 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hou
mixer [17]
Let x = speed of the first car

the second car is 12 km slower so the seconds car speed is x-12

 they each drove 2 hours so 1st car = 2x
2nd car = 2(x-12)
 
they drove 360 km
 so you have 2x + 2(x-12) = 360
 solve for x

2x+2(x-12) = 360

2x + 2x-24 = 360

4x-24 = 360

4x = 384
x = 384/4
x = 96

1st car drove at 96 km per hour

slower car drove at 96-12 = 84 km per hour



5 0
3 years ago
Isabel received 4/7 of the 210 votes for cast for class treasurer. How many votes did she receive? Write your answer in simplest
KengaRu [80]

Answer:

120 votes

Step-by-step explanation:

So one way to solve this is by creating an equation to solve for x.

So we are given 4/7, that will be one side of the equation.  

And we are trying to figure out how many votes out of the 210 she received, so on the other side of the equation we will have x/210, since we are solving for x.  

So 4/7 = x/210

We want to get x alone, so we can multiply 4/7 by 210, which equals 120.

So x equals 120!

8 0
3 years ago
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