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2 years ago

6

The radius of a circle with centre O is 5 cm. The lengths of the chords AB and BC are 6 cm and 8 cm respectively. The midpoints

of the chords are X and Y respectively. Find the perimeter of the quadrilateral OXBY.

1 answer:

Katen [24]2 years ago

6 0

Refer to the attachment

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(12 divided by 3) 2 – (18 divided by 3 2)) < (4 divided by 2)

gladu [14]

Answer:

$(12 \div 3)(2 - (18 \div 32) \\ = 4(2 - \frac{19}{16} ) \\ = 4( \frac{23}{16} ) \\ = \frac{23}{4} \\ since \: (4 \div 2) = 2 \\ \frac{23}{4} is \: not \: < 2 \: but \: its \: > 2$

4 0

3 years ago

Solve the following by first clearing the fractions.<br><br> 1/6x+1/2=1/2x+1/2

levacccp [35]

Answer:

.166x + .5 = .5x +.5

Step-by-step explanation:

3 0

2 years ago

Help me with these math questions........ WITH SCREENIES

Nutka1998 [239]

Answer: 6.3093

<u>Step-by-step explanation:</u>

$3^{\frac{x}{5}} = 4$

$ln3^{\frac{x}{5}} = ln4$

$\frac{x}{5} ln3 = ln4$

xln3 = 5ln4

$x = \frac{5ln4}{ln3}$

x = 6.3093

************************************************************

Answer: 5, 3, $\frac{1}{5}$ , D

<u>Step-by-step explanation:</u>

a) x ≤ 0 so, f(-5) = | -5 | = 5

x ≤ 0 so, f(-3) = | -3 | = 3

x > 0 so, f(5) = $\frac{1}{5}$

b) graph D

************************************************************

Answer: $\frac{\pi}{12}$

<u>Step-by-step explanation:</u>

$\frac{25\pi}{12} - \frac{2\pi}{}$

= $\frac{25\pi}{12} - \frac{24\pi}{12}$

= $\frac{\pi}{12}$

7 0

3 years ago

What is the product of −3 1/4 and −1 1/2? Enter your answer as a mixed number, in simplified form, in the box.

Amiraneli [1.4K]

The product of −3 1/4 and −1 1/2 as a mixed number is $4\frac{7}{8}$ .

The product of −3 1/4 and −1 1/2 as a simplified form is $\frac{39}{8}$

<h3>What is products and mixed numbers?</h3>

Thew products between two terms can be described as the multiplication operation of the the two terms to give a term which is been performed by the use of the operation sign (*) between the two terms.

The mixed number can be defined as the numbers that contains whole numbers as well as the denominators and numerator.

It should be noted that the product of −3 1/4 and −1 1/2 can be done as ( $-3\frac{1}{4} * -1\frac{1}{2} = -\frac{13}{4} * \frac{-3}{2} = \frac{39}{8} = 4\frac{7}{8}$

Read more on mixed number here: brainly.com/question/21610929

#SPJ1

7 0

6 months ago

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-‐impact aerobics = 1</u>

<u>Low-‐impact aerobics = 4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-‐impact aerobics = 1</u>

<u>Low-‐impact aerobics = 4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

7 0

3 years ago