Rearrange the equation into slope intercept form
7x+3y=18
3y=-7x+18
y=-7x/3+18/3 so the slope of the reference line is -7/3
To be perpendicular to this line the slope must be the negative reciprocal of this...mathematically m1*m2=-1. So the slope of our perpendicular line is:
-7m/3=-1
-7m=-3
m=3/7 so our line so far is:
y=3x/7+b, using point (6,8) we can solve for b, the y-intercept
8=3(6)/7+b
8=18/7+b
56/7-18/7=b
38/7=b so our line is:
y=3x/7+38/7 or if you prefer
y=(3x+38)/7
Answer:
C) ∠3 and ∠6 is the CORRECT OPTION.
Step-by-step explanation:
Here, the image is UNATTACHED. Attaching image here for the reference.
Given: JL and MP are parallel.
Alternate Interior angles is a pair of angles formed when there is a common intersecting line between two parallel lines.
As JL and MP are parallel.
and KN is a traversal. So, the pair of Alternate Interior angles so formed are:
a) ∠3 and ∠6
b) ∠4 and ∠5
Now, out of the given options:
A. ∠3 and ∠4 is a LINEAR PAIR
B. ∠1 and ∠6 makes no pair
C. ∠3 and ∠ 6 is a Alternate Interior angles pair
D. ∠5 and ∠6 LINEAR PAIR
Hence, ∠3 and ∠ 6 is a Alternate Interior angles pair.
Step-by-step explanation:
Since x=35 x = 3 5 is a vertical line, the slope is undefined.
Knowing me I would have a jacket with me so I would tie it around my waist.