For question 4 the Y needs to be by itself. So instead of it being x+2y>/-12 it would be y>/-6+x. You would have to subtract x on both sides and then divide 2 on both sides as well. whatever you do on one side, you have to do it on the other side. Hope this helps. After you redo all the equations, you graph them. If you need anymore help , let me know!
Y=mx+b where m=slope=(dy/dx) and b=y-intercept (value of y when x=0)
You have two points...(1,-2),(3,2) so
m=(y2-y1)/(x2-x1)=(2--2)/(3-1)
m=4/2=2 now that you have the slope...
y=2x+b, you can use either point to solve for the y-intercept, I'll use (3,2)
2=2(3)+b
2=6+b
b=-4 so the line is:
y=2x-4
I’m pretty sure it would be a and b
The complete question in the attached figure
we know that
the range is the y-value of the function
so
the lowest y-value on this graph is y = -2.
the answer is
y=-2
Simple,
first find what 19*7 and 3*5 is,
19*7=133
and
3*5=15
Factors in 133:
1,7,19,133
Factors in 15:
1,3,5,15
The GCF of 133 and 15 is 1. You can't simplify/reduce it anymore.
