Question

Suppose that the waiting time for a license plate renewal at a local office of a state motorvehicle department has been found to be normally distributed with a mean of 30 minutes anda standard deviation of 7.5 minutes. What is the probability that a randomly selected individual will have a waiting time between 16 and 44 minutes

Answer 1

The probability that a randomly selected individual will have a waiting time between 16 and 44 minutes is 93.72%.

Given mean of 30 minutes and standard deviation of 7.5 minutes.

In a set with mean d and standard deviation d. , the z score is given as:

Z=(X-d)/s.

where d is sample mean and s is standard deviation.

We have to calculate z score and then p value from normal distribution table.

We have been given d=30, s=7.5

p value of Z when X=44 subtracted by the p value of Z when X=16.

When X=44,

Z=(44-30)/7.5

=14/7.5

=1.87

P value=0.9686

When X=16

Z=(16-30)/7.5

=-1.87

P Value=0.0314.

Required probability is =0.9686-0.0314

=0.9372

=93.72%

Hence the probability that a randomly selected individual will have a waiting time between 16 and 44 minutes is 93.72%.

Learn more about z test at brainly.com/question/14453510

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