The probability that a randomly selected individual will have a waiting time between 16 and 44 minutes is 93.72%.
Given mean of 30 minutes and standard deviation of 7.5 minutes.
In a set with mean d and standard deviation d. , the z score is given as:
Z=(X-d)/s.
where d is sample mean and s is standard deviation.
We have to calculate z score and then p value from normal distribution table.
We have been given d=30, s=7.5
p value of Z when X=44 subtracted by the p value of Z when X=16.
When X=44,
Z=(44-30)/7.5
=14/7.5
=1.87
P value=0.9686
When X=16
Z=(16-30)/7.5
=-1.87
P Value=0.0314.
Required probability is =0.9686-0.0314
=0.9372
=93.72%
Hence the probability that a randomly selected individual will have a waiting time between 16 and 44 minutes is 93.72%.
Learn more about z test at brainly.com/question/14453510
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