Answer:
Mr. Smith is not justified, Mrs. Smith can not be blamed necessarily for being unfaithful
Explanation:
Widow's peak is a dominant trait which means that it will be expressed both in homozygous and heterozygous condition. If "A" is the dominant allele and "a" is the recessive allele, the trait can be represented as AA or Aa.
Both Mr. Smith and Mrs. smith expressed the trait so they can either have AA or Aa genotype. If even one of them had AA genotype all the offspring would have the trait. But if both of them are heterozygous for it:
A a
A AA Aa
a Aa aa
There is 75 % probability of the child to have the trait (AA or Aa) but there is also 25% probability that the child does not express the trait (aa). Their second child belongs to this category and hence Mrs. Smith can not be blamed for being unfaithful.
I would be dead any way so why worry about it go spend time with you family and ignore it family will always be there for you not some weird drugs said to cure you but ends up being the thing to kill you.
I think illusion or distraction
Answer:
he suffered from SCID/severe combined immunodeficiency.
hope this helps! :)
Solution :
Nursing the care plan
<u>Assessment</u>
To assess the respiratory rate, the depth, the abnormal breathing pattern.
Monitor the behavior of the patient and the mental status for the onset of the restlessness and confusion.
Observe for the nail beds and the cyanosis in the skin.
Monitor the oxygen saturation continuously with the help of a pulse oximeter.
<u>Nursing diagnosis</u>
Impaired the gas impaired exchanged related to the airway obstruction as a evidence by the restless and shortness of the breathing and confusion.
<u>Goals</u>
Improving the gas exchange and also improve the breathing pattern.
<u>Intervention</u>
Position the patient with his or her head elevated from the bed in a semi Flower's position.
<u>Evaluation </u>
The patient can breathe normally and then reduce the restlessness and the confusions.
