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EleoNora [17]
2 years ago
13

I would appreciate some help on this if anyone could answer it

Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
7 0

Answer:

Step-by-step explanation:

yea

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Who drove faster? Trevor drove 202 miles in 4 hours Maggie drove 330 miles in 6 hours Nev drove 412 miles in 8 hours Juanita dro
Roman55 [17]

Answer:

Maggie

Step-by-step explanation:

So trevor drove 50.5mph bc 202/4

Maggie 330/6 = 55mph

Nev 412/8=51.5mph

Juanita 261/5= 52.2mph


7 0
3 years ago
38 degrees 2x degrees +6 degrees
ratelena [41]
STEP
1
:
Pulling out like terms

Pull out like factors :

32 - 2x = -2 • (x - 16)

STEP
2
:

Equations which are never true:

2.1 Solve : -2 = 0

This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation:

2.2 Solve : x-16 = 0

Add 16 to both sides of the equation :
x = 16

5 0
2 years ago
Use implicit differentiation to find the points where the parabola defined by x2−2xy+y2+4x−8y+20=0 has horizontal and vertical t
Komok [63]

Answer:

The parabola has a horizontal tangent line at the point (2,4)

The parabola has a vertical tangent line at the point (1,5)

Step-by-step explanation:

Ir order to perform the implicit differentiation, you have to differentiate with respect to x. Then, you have to use the conditions for horizontal and vertical tangent lines.

-To obtain horizontal tangent lines, the condition is:

\frac{dy}{dx}=0 (The slope is zero)

--To obtain vertical tangent lines, the condition is:

\frac{dy}{dx}=\frac{1}{0} (The slope is undefined, therefore the denominator is set to zero)

Derivating respect to x:

\frac{d(x^{2}-2xy+y^{2}+4x-8y+20)}{dx} = \frac{d(x^{2})}{dx}-2\frac{d(xy)}{dx}+\frac{d(y^{2})}{dx}+4\frac{dx}{dx}-8\frac{dy}{dx}+\frac{d(20)}{dx}=2x -2(y+x\frac{dy}{dx})+2y\frac{dy}{dx}+4-8\frac{dy}{dx}= 0

Solving for dy/dx:

\frac{dy}{dx}(-2x+2y-8)=-2x+2y-4\\\frac{dy}{dx}=\frac{2y-2x-4}{2y-2x-8}

Applying the first conditon (slope is zero)

\frac{2y-2x-4}{2y-2x-8}=0\\2y-2x-4=0

Solving for y (Adding 2x+4, dividing by 2)

y=x+2 (I)

Replacing (I) in the given equation:

x^{2}-2x(x+2)+(x+2)^{2}+4x-8(x+2)+20=0\\x^{2}-2x^{2}-4x+x^{2} +4x+4+4x-8x-16+20=0\\-4x+8=0\\x=2

Replacing it in (I)

y=(2)+2

y=4

Therefore, the parabola has a horizontal tangent line at the point (2,4)

Applying the second condition (slope is undefined where denominator is zero)

2y-2x-8=0

Adding 2x+8 both sides and dividing by 2:

y=x+4(II)

Replacing (II) in the given equation:

x^{2}-2x(x+4)+(x+4)^{2}+4x-8(x+4)+20=0\\x^{2}-2x^{2}-8x+x^{2}+8x+16+4x-8x-32+20=0\\-4x+4=0\\x=1

Replacing it in (II)

y=1+4

y=5

The parabola has vertical tangent lines at the point (1,5)

4 0
3 years ago
The sales tax in Bill's state is 6%. Bill bought a Scion having a sales tax of $820. What was the cost of the car? Round to near
kobusy [5.1K]
820 x .6 = 492 + 820 = $1312  Hope that helps
6 0
3 years ago
Can you help me plz.
adelina 88 [10]

Answer:1.885 miles

Step-by-step explanation:Do 0.58 times 3.25 which gives you 1.885.

Hope it helps :)

4 0
2 years ago
Read 2 more answers
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