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2 years ago

If I roll two six-sides dice, what is the probability that the sum of the numbers that show up on the dice is 3 or less?

Mathematics

1 answer:

liq [111]2 years ago

4 0

Answer:

1/12

Step-by-step explanation:

first we have to find all the possibilities of getting a sum of 3 or less: 1+1 or 1+2 and we count the second combination 2 times because the numbers can be on either of the dices so we have a total of 3 possibilities. all the possible pairimg of dice are 6*6=36 because each dice has 6 sides and we can get either of them. so the probability would be the chance of getting a sum of 3 or less divided by all the diff combination which equals 3/36 or 1/12 which is roughly around 8.3%

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How to convert 5x^2-60x+200 to vertex form?

Rom4ik [11]

Y=a(x-h)^2+k

is what vertex form look like. (h,k) is your vertex so in this problem your vertex would be (60,200)

6 0

2 years ago

Find the angles marked with letters. Please help!!

Paladinen [302]

A=34°
B=76°
C and d = 70°
because a triangle is 180° and we know
a+b+c=180
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3 0

2 years ago

Monique borrows $5000 at 5.5% interest compounded daily for 29 days. How much will she owe at the end of 29 days?

slega [8]

Answer:

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount borrowed

From the information given,

P = 5000

r = 9

5.5% = 5.5/100 = 0.055

Assuming they are 365 days in a year

n = 365 because it was compounded 52 times in a year.

t = 29/365 = 0.0794

Therefore,

A = 5000(1 + 0.055/365)^365 × 0.0794

A = 5000(1 + 0.00015)^29

A = 5000(1.00015)^29

A = $5022

7 0

2 years ago

Listed below are the lead concentrations in mu ??g/g measured in different traditional medicines. Use a 0.10 0.10 significance l

laiz [17]

Answer:

We conclude that the mean lead concentration for all such medicines is less than 17 mu.

Step-by-step explanation:

We are given below are the lead concentrations in mu;

6.5 18.5 21.5 5.5 8.5 4.5 4.5 17.5 15.5 20

We have to test the claim that the mean lead concentration for all such medicines is less than 17 mu.

Let $\mu$ = mean lead concentration for all such medicines.

So, Null Hypothesis, $H_0$ : $\mu$ = 17 mu {means that mean lead concentration for all such medicines is equal to 17 mu}

Alternate Hypothesis, $H_A$ : $\mu$ < 17 mu {means that the mean lead concentration for all such medicines is less than 17 mu}

The test statistics that would be used here One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}$ ~ $t_n_-_1$

where, $\bar X$ = sample mean lead concentration = $\frac{\sum X}{n}$ = 12.25 mu

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 6.96 mu

n = sample size = 10

So, test statistics = $\frac{12.25 -17}{\frac{6.96}{\sqrt{10}}}$ ~ $t_9$

= -2.16

The value of t test statistics is -2.16.

Now, the P-value of the test statistics is given by the following formula;

P-value = P( $t_9$ < -2.16) = 0.031

Now, at 0.10 significance level the t table gives critical value of -1.383 for left-tailed test. Since our test statistics is less than the critical value of t as -2.16 < -1.383, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean lead concentration for all such medicines is less than 17 mu.

7 0

3 years ago

Determine where the function is increasing, decreasing, and constant.

joja [24]

The answer is B. Increasing: No where Decreasing: (0,1) Constant: (-2,∞)

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2 years ago