Question

You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of the crate is​

Answer 1

Hello AljakeVillena!

$\huge \boxed{\mathfrak{Question} \downarrow}$

You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of the crate is ?

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

Given,

• mass of crate = 50 kg
• Force you pull it with = 450 N
• Frictional force = 250 N
• Acceleration = ?

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Let's first find the total force/net force acting on the crate. The total force will be :-

• 450 N - 250 N = 200 N.

We subtracted the forces because both the forces act on opposite directions.

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Now, let's find the acceleration of the crate. To find the acceleration we must divide the net force by the mass. So,..

• Acceleration = Force/mass
• a = F/m
• a = 200/50
• a = 4 m/s²

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So, the acceleration of the crate is 4 m/s².

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Hope it'll help you!

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