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3 years ago

What value is equivalent to 2 × 3 + 4 − 6^2? A) -26 B) -22 C) -2 D) 10

Mathematics

2 answers:

marta [7]3 years ago

4 0

Answer:

A) -26

Step-by-step explanation:

2 * 3 + 4 - 6²

Use PEMDAS to figure out the equation.

Pass parenthesis since there are none in the equation.

Evaluate all of the exponents.

2 * 3 + 4 - 36

Evaluate all of the multiplication in the equation.

6 + 4 - 36

Pass division since there isn't any in the equation.

Evaluate all of the addition in the equation.

10 - 36

Evaluate all of the subtraction in the equation.

-26.

Yuliya22 [10]3 years ago

3 0

Answer:

-26

Step-by-step explanation:

2 × 3 + 4 − 6^2

PEMDAS

exponents are first in this equation

2 × 3 + 4 − 36

Then multiply

6 +4 -36

Then add and subtract from left to right

10-36

-26

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The sum of three and four tenths and a number is six and six tenths.

Solnce55 [7]

Hopefully I drew what you described.

The 6.6 represents the total of N + 3.4
We subtract the part we know from the whole /sum/total we know to get the other part.
So 6.6 - 3.4 = N
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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

Hector records his reading times in a journal. His two reading times are 33.56 min and 41.98 min. Liam records his reading times

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2 years ago

Find the difference of (t-8)-(t-15)

Vsevolod [243]

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3 years ago

22. Determine the value of c so that the line

tiny-mole [99]

Answer:

If the lines BC and DE are parallel, the value of c is c=-2

Step-by-step explanation:

We are given line segment BC with end points B(2, 2) and C(9,6) and line segment DE with endpoints D(c, -7) and E(5, -3).

Using slope formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$ we can find point c

When 2 lines are parallel there slope is same.

So, Slope of line BC =Slope of Line DE

$\frac{y_2-y_1}{x_2-x_1}=\frac{y_2-y_1}{x_2-x_1}$

We have:

$x_1=2, y_1=2, x_2=9, y_2=6 \ for \ line \ BC \ and \\\x_1=c, y_1=-7, x_2=5, y_2=-3 \ for \ line \ DE \$

Putting values and finding c

$\frac{6-2}{9-2}=\frac{-3-(-7)}{5-c}\\ \frac{4}{7}=\frac{-3+7}{5-c} \\ \frac{4}{7}=\frac{4}{5-c} \\Cross \ multiply:\\4(5-c)=4*7\\20-4c=28\\-4c=28-20\\-4c=8\\c=\frac{8}{-4}\\c=-2$

So, If the lines BC and DE are parallel, the value of c is c=-2

8 0

3 years ago