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3 years ago

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at least $580 to buy a new Bose sound system. He has $210 in savings and plans to save $30 a week until he has enough money to b

uy one. How many weeks will it take Nick to save enough money to buy the sound system?

1 answer:

rusak2 [61]3 years ago

4 0

Answer:

13 weeks

Step-by-step explanation:

multiply $30 by 13 weeks you get $390 add the $210 and get $600

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What is the prime factor of 236

grin007 [14]

Answer:

Step-by-step explanation:

prime factorization calculator of 326

Positive Integer factors of 326 = 2, 163, 326 divided by 2, 163, gives no remainder. They are integers and prime numbers of 326, they are also called composite number.

326 is a composite number.

Prime factorization: 326 = 2 x 163.

The exponents in the prime factorization are 1 and 1. ...

Factors of 326: 1, 2, 163, 326.

Factor pairs: 326 = 1 x 326 or 2 x 163.

326 has no square factors that allow its square root to be simplified.

8 0

3 years ago

What the answer now

stiks02 [169]

Answer:

35.6 yd²

Step-by-step explanation:

Area of ∆UVW can be solved if we know the lengths of 2 sides and their included angle.

We are Given just 1 side, UV (w). Use the law of sines to find UW (v).

Thus:

$\frac{v}{sin(V)} = \frac{w}{sin(W)}$

W = 137°

w = 19 yd

V = 180 - (137 + 22) = 21° => sum of triangle

v = ??

Plug in the values and solve for v

$\frac{v}{sin(21)} = \frac{19}{sin(137)}$

Multiply both sides by sin(21)

$\frac{v}{sin(21)}*sin(21) = \frac{19}{sin(137)}*sin(21)$

$v = \frac{19*sin(21)}{sin(137)}$

$v = 10 yd$ (approximated)

Find area of ∆UVW:

Area = ½*UV*UW*sin(U)

Area = ½*v*w*sin(U)

= ½*10*19*sin(22)

Area = 35.6 yd² (to nearest tenth)

7 0

3 years ago

Help pls, will mark brainliest

BaLLatris [955]

Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

The n'th term of a Arithmetic Sequence let's say it be ${\sf T_n}$ is given by ;

${\boxed{\bf T_{n}=T_{1}+(n-1)d}}$

Where , <u>d</u> is the common difference

Now , here we are given with ;

${\quad \qquad \sf \blacktriangleright \blacktriangleright \blacktriangleright T_{1}=8 \: and \: T_{5}=-4}$

We have to find the 2nd , 3rd and 4th term respectively ,

Now , by using the above formula , 5th term can be written as ;

${: \implies \quad \sf T_{1}+(5-1)d=T_{5}}$

Putting the values and transposing 1st term to RHS , we have ;

${: \implies \quad \sf 4d = -4-8}$

${: \implies \quad \sf d=-\dfrac{12}{4}}$

${: \implies \quad \sf d=-3}$

Now , as we got the common difference , so we can find out the missing terms now ;

${: \implies \quad \sf T_{2}= T_{1}+(2-1)d}$

${: \implies \quad \sf T_{2}= 8 +d}$

${: \implies \quad \sf T_{2}= 8-3}$

${: \implies \quad \bf \therefore \: T_{2}= 5}$

Now

${: \implies \quad \sf T_{3}= T_{1}+(3-1)d}$

${: \implies \quad \sf T_{3}= 8 +2d}$

${: \implies \quad \sf T_{3}= 8-6}$

${: \implies \quad \bf \therefore \: T_{3}= 2}$

Also ,

${: \implies \quad \sf T_{4}= T_{1}+(4-1)d}$

${: \implies \quad \sf T_{4}= 8 +3d}$

${: \implies \quad \sf T_{4}= 8-9}$

${: \implies \quad \bf \therefore \: T_{4}= -1}$

Now , The given table can be written as ;

${\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}$

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

brainly.com/question/26750175

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3 years ago

Write an equation of the line that passes through (5,9) and is perpendicular to the line y=-1/3x+1

777dan777 [17]

Perpendicular = opposite sign and reciprocal slope
Slope would be 3
Y = 3x + b, plug in point
9 = 3(5) + b, b = -6
Solution: y = 3x - 6

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3 years ago

Prove that Sin2(90-theta)(1+cot2(90-theta))=1

s2008m [1.1K]

Step-by-step explanation:

The Answer is in the photo

8 0

3 years ago