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PIT_PIT [208]
3 years ago
14

Can you please check my answer for me ?(:

Mathematics
2 answers:
Alexandra [31]3 years ago
8 0
Dont doubt yourself you did good!
Vinvika [58]3 years ago
7 0
I don't believe you would shade anywhere, so your work is correct :D 
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Write in equation passing through the point that is parallel to (8,3); y=-1/4x+7
BaLLatris [955]

Answer:

y=-1/4x+5

Step-by-step explanation:

Use the point-slope form which is y-y1=m(x-x1) where m is the slope. In this case, y is equal to 3, and x is equal to 8, and the slope is equal to -1/4. Therefore, the equation will be equal to y-3=-1/4(x-8). Simplify that to get        y-3=-1/4x+2. Simplify this again to get y=-1/4x+5. Therefore, the equation is y=-1/4x+5.

7 0
3 years ago
Read 2 more answers
Regroup hundreds as Tens:<br><br> 8 hundreds 9 tens =
Lilit [14]
89 tens because 8 x10 is 80 add the 9
89
7 0
3 years ago
State whether the given measurements determine zero, one, or two triangles.
Lady bird [3.3K]
I bet you're doing the Law of Sines right now. If you use the law of sines you find out that angle A is a 90 degree angle. There is only one triangle you can make with these measurements because if you have one angle of 30 and another of 90, the 3rd angle has to be a 60 degree angle. So it is a special right triangle, 30-60-90
8 0
3 years ago
Is my answer correct? if not please correct me
elena-s [515]

Using the given equation y-3 = 3/4(x+2)


Give Y a value and then solve for x:


If y = 0 the equation is now:

0 -3 = 3/4(x+2)

Solve for x:

-3 = 3/4x + 1.5

-4.5 = 3/4x

x = -4.5 / 3/4

x = -6


So the first point would be (-6,0)


Now make x 0 and solve for y:

y -3 = 3/4(0+2)

y-3 = 0 + 1.5

y = 4.5

So the 2nd point would be (0,4.5)


You are close, but the dot you have on y=4, needs to be moved up to 4.5.


8 0
3 years ago
Find the distance between the points c ( 6, 5) and D(-3, 1),
svet-max [94.6K]

Answer:

see explanation

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (6, 5) and (x₂, y₂ ) = (- 3, 1)

d = \sqrt{(-3-6)^2+(1-5)^2}

  = \sqrt{(-9)^2+(-4)^2}

  = \sqrt{81+16}

  = \sqrt{97} ≈ 9.85 ( to 2 dec. places )

4 0
2 years ago
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