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vazorg [7]
3 years ago
8

Which table shows a proportional relationship between x and y?

Mathematics
2 answers:
nekit [7.7K]3 years ago
7 0

Step-by-step explanation:

I do not know<33

Oliga [24]3 years ago
6 0

Answer:

c is the answer

Step-by-step explanation:

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PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST
emmasim [6.3K]
Answer = 314.2

Area of cyclinder:
Area at base x height

Pi = 3.142

5^2 x 3.142 = 78.55

78.55 x 4 = 314.2
5 0
3 years ago
Consider the Polynomial P(x)=x^3-5x^2-x+5. is (x-5) a factor?
Alborosie

Answer:

Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

Step-by-step explanation:

<u>Step 1:  Factor</u>

p(x) = x^3 - 5x^2 - x + 5

<em>p(x) = (x - 5)(x + 1)(x - 1)</em>

<em />

<em>Yes, the remainder is 0 so, x-5 is a factor of p(x)</em>

<em />

Answer:  Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

8 0
3 years ago
Six oranges cost $1.50. how much does 15 oranges cost?<br>​
kati45 [8]

Answer:

3.75 for 15 oranges

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The problem
Afina-wow [57]

Answer:

Step-by-step explanation:

In the given division, when 24.725 is divided by 215,

Step 1 is the wrong step.

Quotient in first step will be 0.1 .

Part C.

215) 24.725 (0.115

      <u> 215</u>

          322

          <u>215</u>

           1075    

           <u>1075</u>

                0

Therefore, the correct way to divide should be as agove.

Quotient after division should be 0.115.

6 0
3 years ago
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
4 years ago
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