The area of the square is greater than the circle: the area of the circle is pi(r)^2 while the area of the square is length times width. The area of the circle is about 12.5 while the area of the square is 16.
Answer:
40°, 95°, 105°, and 160°
Step-by-step explanation:
Let the smallest angle be x.
Measures of the 3 angles can be expressed as:



The sum of all angles in a quadrilateral = 360°.
Therefore, 
Solve for x






The smallest angle = 40°
Plug in the value of x in the earlier stated expressions to find the measure of the other angles:



Answer:
-790
Step-by-step explanation:
Answer:
Step-by-step explanation:
![6k^3+10k^2-56k\\2k(3k^2+5k-28)\\=2k[3k^2+12k-7k-28]\\=2k[3k(k+4)-7(k+4)]\\=2k(k+4)(3k-7)](https://tex.z-dn.net/?f=6k%5E3%2B10k%5E2-56k%5C%5C2k%283k%5E2%2B5k-28%29%5C%5C%3D2k%5B3k%5E2%2B12k-7k-28%5D%5C%5C%3D2k%5B3k%28k%2B4%29-7%28k%2B4%29%5D%5C%5C%3D2k%28k%2B4%29%283k-7%29)
common factor is 3k-7