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andrezito [222]
3 years ago
15

Which term of ap 30,27,24is0

Mathematics
1 answer:
son4ous [18]3 years ago
8 0

Answer:

11th term is 0

Step-by-step explanation:

30, 27 , 24 ,......0

a = first term = 30

Common difference = second term - first term = 27 - 30 = -3

nth term = a+(n-1)*d

a + (n-1)d = 0

30 + (n - 1) *(-3) = 0

30 + n*(-3) -1*(-3) = 0

30 - 3n + 3 = 0

      -3n + 33 = 0

               -3n = -33

                   n = -33/-3

n = 11

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The larger of two numbers is 15 more than 3 times the smaller number. If the sum of the two numbers is 63 find the numbers
scoray [572]

Answer:

X = 51

Y = 12

Step-by-step explanation:

2 numbers: (Larger) Number 1 is x and Number 2 is y

The equation is x + y = 63

  • x = 3y +15
  • y = y

New equation is:

  • 3y + 15 + y = 63

Combine like variables:

  • 4y + 15 = 63

Solve:

  • 4y + 15 - 15 = 63 - 15
  • 4y = 48

Divide 4 from each side:

  • <em><u>y = 12</u></em>

To find x fill in the variables from the 'x =' equation:

  • x = 3y + 15
  • x = 3( 12) + 15
  • <em><u>x = 51</u></em>
3 0
3 years ago
Please help!
seropon [69]

Answer:

0.246¯¯¯¯ written as a fraction in simplest form?

the answer is 1000÷246

8 0
3 years ago
A swimsuit is in sale for 45.50. if the sales price is discounted 5%from the orginal price. what was the original price. round t
AnnyKZ [126]
The answer is 42.80 , 2.28 is what they saved and i got the .80 cents because i rounded up from .78
8 0
3 years ago
If f(x) = 4x 6 and g(x) = x + 2,<br> what is (fºg)(7)?
laiz [17]

Step-by-step explanation:

(f○g)(7)

= f(g(7))

g(7) = 7 + 2

= 9

f(9) = 4(9) .....

......

3 0
3 years ago
Cargo ships arrive at a loading dock at a rate of 2 per day. The dock has the capability of handling 3 arrivals per day. How man
Vsevolod [243]

Answer:

4 days

Step-by-step explanation:

We need to use the probability functions of each of the intervals to know the Probability number and then use it in the expected value.

P(x>3 cargo ships) = 1-P(x<=3)

P(x>3) = 1-P(x<=3)

P(x>3) = 1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)]

P(x>3) = 1 - [\frac{e^{-2}2^0}{01}+\frac{e^{-2}2^1}{11}+\frac{e^{-2}2^2}{21}+\frac{e^{-3}2^3}{31}]

P(x>3) = 1- [0.1353(1+2+2+1.33)]

P(x>3) = 1-0.856

P(x>3) = 0.1431

Als n=30, expected number is

E(x) =30*P(x>3)

E(x) = 30*0.1431

E(x) = 4.293

I expect 4.293 or 4 days per month the block being unable to hanlde all arriving ships

6 0
3 years ago
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