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3 years ago

Pablo swims 1 length of a swimming pool. What unit would be best for measuring that length of the pool?

Mathematics

1 answer:

drek231 [11]3 years ago

6 0

Answer:

kiloliters

Step-by-step explanation:

The amount of water a family uses in a year is a large amount of water - more than the amount of water in a pool! This means kiloliters would be the best unit of measurement.

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The larger of to numbers is 12 more than the smaller. Their sum is 84. What are the two numbers?

Nataly_w [17]

36 and 48

a = b+12
a+b = 84

(b+12) + b =84
2b +12 = 84
2b = 72
b= 36

a = b + 12
a = 36 + 12
a = 48

3 0

4 years ago

Find the value of x.

nikklg [1K]

Answer:

x = 13

Step-by-step explanation:

Sum or interior angles of a triangle is 180,

6x + 19 + 5x - 15 + 3x - 6 = 180

6x + 5x + 3x + 19 - 15 - 6 = 180

14x + 19 - 21 = 180

14x - 2 = 180

14x = 180 + 2

14x = 182

x = 182 / 14

x = 13

5 0

3 years ago

Point A is located at (-5, 2) on a coordinate grid. Point A is translated 4 units to the right and 2 units down to create point

HACTEHA [7]

The correct solution is A thanks

3 0

3 years ago

Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel

GarryVolchara [31]

Answer:

The unusual $X$ values for this model are: $X = 0, 1, 2, 7, 8$

Step-by-step explanation:

A binomial random variable $X$ represents the number of successes obtained in a repetition of $n$ Bernoulli-type trials with probability of success $p$ . In this particular case, $n = 8$ , and $p = 0.53$ , therefore, the model is ${8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}$ . So, you have:

$P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024$

$P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215$

$P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848$

$P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912$

$P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695$

$P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431$

$P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371$

$P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442$

$P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062$

The unusual $X$ values for this model are: $X = 0, 1, 7, 8$

6 0

3 years ago

Read 2 more answers

Someone ask me to solve this.

Semenov [28]

X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 -----> 3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

3k +4h =4 ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4 or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4 , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .

6 0

3 years ago